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Scilla [17]
3 years ago
13

Match each type ol energy with its description

Physics
2 answers:
mel-nik [20]3 years ago
6 0
It is B I sloved it
miskamm [114]3 years ago
4 0

Answer:

B

Explanation: yes

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Answer:

D.)it orbits near the Kepler belt

Explanation:

The Kuiper belt is an area similar to the asteroide belt extending from the orbit of Neptune to about 50 AU from the Sun. It mainly consists of icy asteroids and dwarf planets, which are rocky objects big enough to be defined as planet but that do not have enough gravity to clear their orbit from other obejcts.

Pluto was discovered in 1930 - initially it was classified as a planet, although it is much smaller than the other 8 planets of the Solar System. However, it has been recently de-classified to dwarf planet because its gravity is not enough to clear its orbit from other objects (asteroids). Pluto is located inside the Kuiper belt, so option D is correct. Other dwarf planets in the Kuiper belt are for instance Haumea and Makemake.

8 0
3 years ago
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A ball is thrown up in the air. When it falls back down and reaches the ground, it's final downward velocity is 8.0 m/s. What wa
hram777 [196]
Given : Time taken to reach the maximum height t=3 s a=−g=−10m/s
2


The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×3 ⟹u=30 m/s

Using S=ut+
2
1
​
at
2

∴ S=30×3+
2
1
​
×(−10)×3
2
=45m
8 0
2 years ago
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What average force is required to stop a 980 kg car in 9.0 s if the car is traveling at 91 km/h ?
kozerog [31]
Newton's second law of motion:
F=ma
a =  \frac{v}{t}
You convert from km/h to m/s by dividing by 3.6:
v = 91 \div 3.6
v = 25.3 \:  \frac{m}{s}
Then a is:
a =  \frac{25.3}{9}
a = 2.8  \frac{m}{s {}^{2} }
Then:
F=(980)(2.8)=2744 N
5 0
2 years ago
5 10 points Sanzida conducted an experiment that required a wire carrying a current to be wrapped around a metal core. When she
stellarik [79]

The current in the wire has created a magnetic field with its north pole at the top of the rod.  A magnetic field influences electric currents.

<h3>What is a magnetic field?</h3>

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The magnetic field also refers to the one where magnetic forces act to shape an electrical current.

The only material and/or body capable of altering an electrical current in a magnetic field is the presence of another magnetic field.

Learn more about magnetic fields here:

brainly.com/question/14411049

7 0
2 years ago
Consider two aluminum rods of length 1 m, one twice as thick as the other. If a compressive force F is applied to both rods, the
ICE Princess25 [194]

Complete Image

Consider two aluminum rods of length 1 m, one twice as thick as the other. If a compressive force F is applied to both rods, their lengths are reduced by  \Delta L_{thick}and \Delta L_{thin}, respectively.The ratio ΔLthick rod/ΔLthin rod is:

a.) =1

b.) <1

c.) >1

Answer:

The ratio is less than 1 i.e \frac{1}{2}   option B is correct

Explanation:

The Young Modulus of a material is generally calculated with this formula

               E = \frac{\sigma}{\epsilon}

 Where \sigma is the stress = \frac{Force}{Area}

             \epsilon is the strain = \frac{\Delta L}{L}

  Making Strain the subject

              \epsilon = \frac{\sigma}{E}

now in this question we are that the same tension was applied to both wires so

      \frac{\sigma}{E} would be constant

Hence

                 \frac{\Delta L}{L} = constant

for the two wire we have that

                  \frac{\Delta L_1}{L_1} = \frac{\Delta L_2}{L_2}

      Looking at young modulus formula

                E = \frac{\frac{F}{A} }{\frac{\Delta L}{L} }

                    E * \frac{\Delta L }{L}  = \frac{F}{A}

                  A * \frac{\Delta L}{L}  = \frac{F}{E}

Now we are told that a comprehensive force is applied to the wire so for this question

                \frac{F}{E} is constant

And given that the length are the same

so  

     A_1 \frac{\Delta L_{thin}}{L_{thin}} = A_2 \frac{\Delta L_{thick}}{L_{thick}}

Now we are told that one is that one rod is twice as thick as the other

So it implies that one would have an area that would be two times of the other

  Assuming that

           A_2 = 2 A_1

So

       A_1 \frac{\Delta L_{thin}}{L_{thin}} = 2 A_1 \frac{\Delta L_{thick}}{L_{thick}}

     \frac{\Delta L_{thin}}{L_{thin}} = 2 \frac{\Delta L_{thick}}{L_{thick}}

From the question the length are equal

      \Delta L_{thin} =2  \Delta L_{thick}

So  

       \frac{\Delta L_{thick}}{\Delta L_{thin} } = \frac{1}{2}

Hence the ratio is less than 1

       

6 0
2 years ago
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