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NeX [460]
2 years ago
8

The half-life for P-32 is 14.3 days. What fraction of a sample of P-32 will be left after 42.9 days?

Physics
1 answer:
mafiozo [28]2 years ago
6 0

Answer: At one half-life (14.3 days) 230 mg of the P-32 would remain. at two half-lives (14.3 + 14.3 or 28.6 days) 115 mg of the P-32 would remain. at three half-lives (14.3 + 14.3 + 14.3 or 42.9 days) 57.5 mg of the P-32 would remain.

Explanation:

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How much heat would be needed to completely evaporate 31.5 g of boiling water at a temperature of 100 "C? Express your answer in
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When an MRI machine are use to capturing images of a person's body the produce extremely powerful magnetic fields what might be
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2 years ago
Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each mo
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Answer:

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

Explanation:

Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each moving at the same speed v when they collide at the origin of the coordinates and stick together. After the collision, the masses move at an angle −θ2 with respect to the +x axis at speed v2 .1. What was the angle φ?

from the principle of momentum

In a system of colliding bodies,we know that the total momentum before collision will equal to the total momentum after collision.

Take note that momentum is the product of mass and velocity

momentum before collision=momentum after collision

mass, m

u=initial velocity of the identical masses

v2=the common velocity after the collision

Note that the collision is inelastic , since they both moved with the same velocity

umcosφ+umcosφ=(m+m)v2cos−θ2

2mucosφ=2mv2cos−θ2

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

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