Answer:
the work done by friction on the car is 524,582 J.
Explanation:
Given;
mass of the roller coaster, m = 800 kg
distance moved by the coaster, d = 225 ft = 68.58 m
final velocity of the coaster, v = 80 mi/h = 35.76 m/s
The time taken for the coaster to drop down the hill is calculated as;
The work done by friction on the car is calculated as;
Therefore, the work done by friction on the car is 524,582 J.
Answer
given,
mass of the drop, m = 0.0014 g
speed of the drop, u = 8.1 m/s
a) Change in momentum is equal to impulse
final velocity of the drop, v = 0 m/s
J = m ( v - u )
J = 0.0014 x 10⁻³ x ( 0 - 8.1 )
J = -1.134 x 10⁻⁵ kg.m/s
impulse of the roof = - J = 1.134 x 10⁻⁵ kg.m/s
b) time, t = 0.37 m s
impact of force = ?
we know
J = F x t
1.134 x 10⁻⁵ = F x 0.37 x 10⁻³
F = 0.031 N
the magnitude of the force of the impact is equal to F = 0.031 N
Answer:
Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force. ... Forces that cause a change in the motion of an object are unbalanced forces.
