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DedPeter [7]
3 years ago
7

A block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. What must be true about force

of static friction f on the block?
Physics
2 answers:
galina1969 [7]3 years ago
6 0

Answer:

μ =tanθ

Explanation:=

The ratio of the force of static friction and the normal reaction is equal to tanθ. F=mgsinθ. R = mgcosθ.

μ=tanθ

Aliun [14]3 years ago
5 0

Answer: So the static friction force must be equal to g*m*cos( θ)

Explanation: The force downwards of the block will be equal to the component with respect of where it can move.

So the force downwards will be:

F = Weight*cos( θ)

And we know that the weight is w = -m*g where g is the gravitational acceleration.

F = -g*m*cos( θ)

And we know that the block is at rest, so the net forces on it are equal to zero, this means that the gravitational force must be canceledby other one, and this can be the static friction force.

So the static friction force must be equal to g*m*cos( θ)

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zepelin [54]

Answer:

7.41 x 10^-10 J

Explanation:

m = 4.5 kg

M = 6.3 kg

d = 1.7 m

The formula for the gravitational potential energy is given by

U = \frac{-GMm}{d}

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

U = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{1.7}

U = - 1.112 x 10^-9 J

Now the separation is tripled, d' = 3 x d = 3 x 1.7 m = 5.1 m

Let the potential energy is U'

The formula for the gravitational potential energy is given by

U' = \frac{-GMm}{d'}

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

U' = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{5.1}

U' = - 3.71 x 10^-10 J

the work done is equal to the change in potential energy

W = U' - U

W = - 3.71 x 10^-10 + 1.112 x 10^-9

W = 7.41 x 10^-10 J

7 0
4 years ago
Lauren is comparing rocks from two different locations. She has the following
telo118 [61]

Answer:

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3 years ago
A force of 10 N causes a spring to extend by 20 mm. Find a) the spring constant of the spring in N/m b) the extension of the spr
suter [353]

(a) The spring constant is 500 N/m.

(b) The extension of the spring when 25 N force is applied is 0.05 m.

(c) The applied force to cause an extension of 5 mm is 2.5 N.

The given parameters:

  • Applied force, F = 10 N
  • Extension of the spring, x = 20 mm

The spring constant is calculated as follows;

F = kx\\\\k = \frac{F}{x} \\\\k = \frac{10}{20 \times 10^{-3}} \\\\k = 500 \ N/m

The extension of the spring when 25 N force is applied is calculated as follows;

F = kx\\\\x = \frac{F}{k} \\\\x = \frac{25}{500} \\\\x = 0.05 \ m

The applied force to cause an extension of 5 mm is calculated as follows;

F = kx\\\\F = 500 \times 5 \times 10^{-3}\\\\F = 2.5 \ N

Learn more about Hook's law here: brainly.com/question/12253978

7 0
3 years ago
Mass is the amount of matter in an object what describes the amount of space the object takes up?
saveliy_v [14]
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2 years ago
A. A light wave moves through glass (n=1.5) at an angle of 25°. What angle will it have when it moves from the glass into air (n
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PART A)

By Snell's law we know that

n_1sin i = n_2 sin r

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n_1 = 1.5

i = 25 degree

n_2 = 1

now from above equation we have

1.5 sin25 = 1 sin r

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so it will refract by angle 39.3 degree

PART B)

Here as we can see that image formed on the other side of lens

So it is a real and inverted image

Also we can see  that size of image is lesser than the size of object here

Here we can use concave mirror to form same type of real and inverted image

PART C)

As per the mirror formula we know that

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

\frac{1}{d_i} + \frac{1}{60} = \frac{1}{20}

d_i = 30 cm

so image will form at 30 cm from mirror

it is virtual image and smaller in size

3 0
4 years ago
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