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Svetllana [295]
3 years ago
10

What is the magnitude of velocity for a 2000 kg car possessing 3000 kgm/s of momentum

Physics
2 answers:
Alchen [17]3 years ago
7 0

Answer: 1.5m/s

Explanation:

Momentum of a body is defined as the product of the mass of the body and its velocity.

Momentum (p) = mass(m) × velocity (v)

Momentum = 3000 kgm/s

Mass = 2000kg

Velocity (v) = Momentum/mass

Velocity = 3000/2000

Velocity of the body will be 1.5m/s

Alex3 years ago
4 0

For this case we have that by definition, the momentum is given by:

p = mv

Where,

  • <em>m: mass </em>
  • <em>v: speed </em>

Therefore, replacing values we have:

3000 = (2000) v

From here, we clear the value of the speed:

v = \frac {3000} {2000}\\v = 1.5 \frac {m} {s}

Answer:

The magnitude of velocity is:

v = 1.5 \frac {m} {s}

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  2. One common use of convex mirror is as rear-view mirrors in automobiles vehicles.

<h3>What is a concave mirror?</h3>

A concave mirror is also referred to as a converging mirror and it can be defined as a type of mirror that is designed and developed with a reflective surface that is typically curved inward and away from the source of light.

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<h3>What is a convex mirror?</h3>

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8 0
2 years ago
Copernicus and other astronomers before him thought that celestial bodies followed a _____ orbital path.
murzikaleks [220]
The correct answer is circular. Copernicus and other astronomers before him thought that celestial bodies followed a circular orbital path. Copernicus was a Polish astronomer that concluded that the sun is at rest near the center of the universe and the earth is revolving around it annually. This theory is called heliocentric. 
6 0
3 years ago
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Answer:

When equal and opposite forces meet each other, it results in motion and they would repel away from each other, causing the asteroid to be sent away from the earth.

Explanation:

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3 years ago
A 1.0 kg rock is thrown straight upward with an initial speed of 8.0 m/s. What is its speed
Ronch [10]

Answer:5.7m/s

Explanation:

Mass=1kg

Initial velocity=u=8m/s

height=h=1.6m

Final velocity =v

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v^2=u^2-2xgxh

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√(v^2)=√(32.64)

v=5.7

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8 0
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