Since ![[0,4]=[0,1]\cup(1,4]](https://tex.z-dn.net/?f=%5B0%2C4%5D%3D%5B0%2C1%5D%5Ccup%281%2C4%5D)
, we can rewrite the integral as
Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:
Both integrals are quite immediate: you only need to use the power rule
to get
![\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E11-3t%5E2%5C%3Bdt%20%3D%20%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%2C%5Cquad%20%5Cint_1%5E4%202t%5C%3B%20dt%20%3D%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4)
Now we only need to evaluate the antiderivatives:
![\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15](https://tex.z-dn.net/?f=%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%20%3D%201-1%5E3%3D0%2C%5Cquad%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4%20%3D%204%5E2-1%5E2%3D15)
So, the final answer is 15.
I believe it is A. Hope this helps.
Answer: left 7 units, up 4 units, and vertical compression
Step-by-step explanation:
Given
The function is 
First shift it to the left by 7 units, so the function becomes
Now compress it to make it one-third
Now, sift the graph upward by 4 units
Thus , the conditions are left 7 units, up 4 units, and vertical compression.
Answer:
5. f(x) = 10,000 (1.5)^x
Step-by-step explanation:
We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.
Let's test it.
Initial:
10,000
After 1 year
10,000 + (.5*10000)
10,000 + 5000 = 15,000
After 2 years
15,000 + (.5*15000)
15,000 + 7500 = 22,500
Let's try our equation.
f(x) = 10,000 (1.5)^x
x = 2
10,000(1.5)^2
10,000(2.25) = 22,500
The same!
