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Vadim26 [7]
3 years ago
10

Which one is bigger 7/11 or 6/8

Mathematics
2 answers:
shtirl [24]3 years ago
5 0

Answer: 7/11

Step-by-step explanation:

pav-90 [236]3 years ago
5 0

Answer:

6 ÷ 8 = .75

7 ÷ 11 ≈ .636363

Therefore, 6/8 is bigger.

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2 years ago
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The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.D1d2, where d1 and d2 are the l
Gelneren [198K]

Answer:

d1=2A/d2

d2=2A/d1

Step-by-step explanation:

The options of this question are:

1. d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2Ad₁

Given:

A=1/2(d1*d2)

Multiply both sides by 2

We have,

2A=d1*d2

Divide both sides by d2

2A/d2=d1*d2/d2

2A/d2=d1

Therefore, d1=2A/d2

Similarly, from the previous equation

2A=d1*d2

Divide both sides by d1

2A/d1=d1*d2/d1

2A/d1=d2

Therefore,

d2=2A/d1

Options

2. d₁= 2A/d₂

4. d₁= 2A/d₂

7 0
3 years ago
What is the five-number summary for this data set?
Natali [406]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a
laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x

So, the mean of 11 consecutive integers is the 6th integer.

4 0
3 years ago
What one of these numbers is not like the others? 25,16,49,63,81
labwork [276]

16, because all the other numbers are odd and 16 is even

8 0
3 years ago
Read 2 more answers
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