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guapka [62]
3 years ago
13

The quotient of 15x^4y^2-30x^2y^3+45xy/5xy is______ .When this quotient is divided by ______, the result is x^3y-2xy^2+3

Mathematics
1 answer:
Daniel [21]3 years ago
7 0
This quotient is 48divide by5
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Add the following two numbers in scientific notation.
strojnjashka [21]

Answer:

3.31 x 10^4

Step-by-step explanation:

3.111 x 10^4 is 31110

2 x 10^3 is 2000

31110 + 2000 = 33100 or 3.31 x 10^4

4 0
1 year ago
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If the policy premium on a 30 year $1,000,000 term life policy for a 35-year-old female is increased to $714, what is the percen
Andru [333]
I believe the answer might be B
3 0
3 years ago
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2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
On a number line, A is at 5 and B is at 50. Point X is the midpoint. Point T is 2/3 of the way from X to B. Determine the coordi
Lemur [1.5K]

Number lines are used to represent points at regular interval.

The coordinate of point T on the number line is: 46.5

Given that:

A =5

B = 50

The coordinate of X at the midpoint is:

X = \frac{B + A}{2}

So, we have:

X = \frac{50+5}{2}

X = \frac{55}{2}

X = 27.5

Point T is at 2/3 from X to B.

The coordinate of T is calculated using:

T = X + \frac 23 (B - X + 1)

So, we have:

T = 27.5 + \frac 23 (55 - 27.5 + 1)

T = 27.5 + \frac 23 (28.5)

T = 27.5 + 19

T = 46.5

<em>Hence, T is located at 46.5</em>

Read more about number lines at:

brainly.com/question/18611090

6 0
2 years ago
If x/y + y/x = -1 , find the value of x^3 - y^3
marin [14]

Answer:

  0

Step-by-step explanation:

Multiplying the first equation by xy, we have ...

  x^2 +y^2 = -xy

Factoring the expression of interest, we have ...

  x^3 -y^3 = (x -y)(x^2 +xy +y^2)

Substituting for xy using the first expression we found, this is ...

  x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0

The value of x^3 -y^3 is 0.

7 0
3 years ago
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