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xxTIMURxx [149]
3 years ago
5

Increase 2850 by 18%

Mathematics
1 answer:
Romashka [77]3 years ago
4 0
First we find 18% of 2850

= 18/100  * 2850 = 513    Use your calculator.

Since we are increasing by 18%, we add 513 t0 2850

= 2850 + 513 =  3363
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Shirley is decorating the gym for a party she has five rolls of blue streamer and 7 rolls of green streamer if each roll of blue
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Answer:

1043ft

Step-by-step explanation:

1 roll of blue streamer is 94 ft long

1 roll of green streamer is 89ft long

She has 5 rolls of blue streamer and 7 rolls of green streamer.

If 1 blue roll has a length of 94ft, 5 rolls will have a length of 5 × 94

If 1 green roll has a length of 89ft, 7 rolls will have a length of 7 × 89

The total feed of streamer she has to decorate with is calculated as follows:

(5 × 94)ft + (7 × 89)ft = 470 + 623 = 1043ft.

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4 years ago
josue has 3 chicken pot pies that he cuts into thirds.How many 1/3 size chicken pot pies peices does he have
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3 years ago
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What is 45% of 40 in part, whole, and percent?
Iteru [2.4K]
The answer is eighteen.
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3 years ago
Charlie is a car salesman. He earns $800 plus a 9% commision on all of his sales for the week. If charlie received a paycheck fo
Hunter-Best [27]

Question

Charlie is a car salesman. He earns $800 plus a 9% commision on all of his sales for the week. If charlie received a paycheck for $1916 this week, how much were his total sales?


Answer:

<h2>1240</h2>

Step-by-step explanation:

1916 - 800 = 1116 (commissions)

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4 0
3 years ago
A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro
Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

5 0
3 years ago
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