Answer:
Step-by-step explanation:
7.
2y² * 3x = 6xy²
8.
4v³ * vu²
= 4v⁴u²
9.
4a³b² * 3a⁻⁴b⁻³
= 12a⁻¹b⁻¹
10.
x²y⁻⁴ * x³y²
11.
(x²)⁰ = 1
12.
(2x²)⁻⁴
4 and 2 since 6+2 is 8 and 8 has two factors which are 4 and 2.
I hope this helps you
x+3/2x-1=-2
x+3= -2 (2x-1)
x+3= -2.2x-2. (-1)
x+3= -4x+2
x+4x=2-3
5x= -1
x= -1/5
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
When dividing two terms with the same base, subtract the exponent in the denominator from the exponent in the numerator: Power of a Power: To raise a power to a power, multiply theexponents.
