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liq [111]
3 years ago
12

Randy has two 28-pound blocks of ice for his snow cone stand. 1). How many pounds of ice does randy have at his snow cone stand?

2). How many tons of ice is there? Write your answer from number 2 as a fraction and a decimal.
Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

Randy has 56 pound blocks of ice for his snow cone stand

Tons of ice is 0.028 tons or \frac{7}{250} \text{ tons }

<em><u>Solution:</u></em>

Randy has two 28-pound blocks of ice for his snow cone stand

<em><u>1). How many pounds of ice does randy have at his snow cone stand?</u></em>

Calculate the total pounds that Randy has

Total pounds = 2 x 28 = 56

Thus Randy has 56 pound blocks of ice for his snow cone stand

<em><u>2) How many tons of ice is there?</u></em>

Total pounds of ice = 56 pounds

So we have to convert 56 pounds to tons

Use the conversion factor

1 pound = 0.0005 ton

Therefore, 56 pounds is equal to,

56 pound = 0.0005 x 56 tons = 0.028 tons

Thus in decimal we got, 0.028 tons

Convert to fraction form,

0.028 = \frac{0.028}{1000} \times 1000 = \frac{28}{1000} = \frac{7}{250}

Thus tons of ice is 0.028 tons or \frac{7}{250} \text{ tons }

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Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
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Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

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Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

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q=All the positive/negative factors of 3

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q=\pm 1,\pm 3

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f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

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f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


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