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4 years ago

How many total atoms are represented by the formula below? 4H2SO4

Chemistry

2 answers:

Dmitry_Shevchenko [17]4 years ago

8 0

Answer:

its either 10 or 11

kifflom [539]4 years ago

5 0

Answer:

10 atoms

Explanation:

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Which describes any substance that shatters or breaks easily? malleable brittle volatile ductile

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Answer:

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3 years ago

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If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength?

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3 years ago

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A scientist measures the standard enthalpy change for the following reaction to be 81.1 kJ :2CO2(g) + 5 H2(g)C2H2(g) + 4 H2O(g)B

posledela

<u>Answer:</u> The enthalpy of the formation of $CO_2(g)$ is coming out to be -410.8 kJ/mol.Z

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

For the given chemical reaction:

$2CO_2(g)+5H_2(g)\rightarrow C_2H_2(g)+4H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(C_2H_2(g))})+(4\times \Delta H^o_f_{(H_2O(g))})]-[(2\times \Delta H^o_f_{(CO_2(g))})+(5\times \Delta H^o_f_{(H_2(g))})]$

We are given:

$\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(H_2(g))}=0kJ/mol\\\Delta H^o_f_{(C_2H_2(g))}=226.7kJ/mol\\\Delta H^o_{rxn}=81.1kJ$

Putting values in above equation, we get:

$81.1=[(1\times (226.7)})+(4\times (-241.8))]-[(2\times \Delta H^o_f_{(CO_2(g))})+(5\times (0))]\\\\\Delta H^o_f_{(CO_2(g))}=-410.8kJ/mol$

Hence, the enthalpy of the formation of $CO_2(g)$ is coming out to be -410.8 kJ/mol.

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3 years ago

Which statement explains the kinetic theory of heat?

Naddik [55]

The theory that states that heat is the result of the movement of particles in a system.

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3 years ago

Butane is a fuel. Its melting point is - 140 °C and its boiling point is -1 °C.

Damm [24]

Answer:

butane will be in gaseous state at 25 degrees and will be solid at -150 degrees.

Explanation:

As 25degrees is the room temperature so the state of butane at 25 degrees will be gaseous while the butane will freeze at -150degrees as it's beyond its melting point, it means it melts at -140degrees , it clearly shows that it exists in solid state before -140degrees.,

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3 years ago