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olya-2409 [2.1K]
3 years ago
9

I just started learning about kinetic molecular theory, and I’m not sure how to answer the question circled below

Chemistry
1 answer:
lions [1.4K]3 years ago
7 0

Answer : The value of 'R' is 0.0821\text{ L atm }mol^{-1}K^{-1}

Solution : Given,

At STP conditions,

Pressure = 1 atm

Temperature = 273 K

Number of moles = 1 mole

Volume = 22.4 L

Formula used :     R=\frac{PV}{nT}

where,

R = Gas constant

P = pressure of gas

T = temperature of gas

V = volume of gas

n = number of moles of gas

Now put all the given values in this formula, we get the values of 'R'.

R=\frac{(1atm)\times (22.4L)}{(1mole)\times (273K)}

R=0.0821\text{ L atm }mol^{-1}K^{-1}

Therefore, the value of 'R' is 0.0821\text{ L atm }mol^{-1}K^{-1}.

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How much Ca(NO3)2 should be weighed out to have 0.650 mol?A) 66.4 g.B) 97.68.C) 107 g.D) 133 g.E) 165 g.
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