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nalin [4]
3 years ago
14

Mercury turns to a vapor at 629.88 K. How much heat is lost when 75.0 g of mercury vapor at 650 K condenses to a liquid at 297 K

?
Chemistry
1 answer:
notsponge [240]3 years ago
4 0

Answer:

- 3706.5 J.

Explanation:

The heat lost by the copper can be calculated using the formula:

Q = m.C.ΔT, where,

Q is the amount of heat lost by the mercury,

m is the mass of the copper <em>(m = 75.0 g)</em>,

C is the specific heat of Hg <em>(C = 0.140 J/g.°C)</em>,

ΔT is the temperature difference (the final temperature - the initial temperature<em> (ΔT = (297 K - 273) °C - (650 K - 273) °C = - 353 °C)</em>.

∴ The amount of heat lost by the mercury Q = m.C.ΔT = (75.0 g) (0.140 J/g.°C) (- 353 °C) = - 3706.5 J.

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Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.

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Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:

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More on calculating mass from number of moles can be found here: brainly.com/question/12513822

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