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nalin [4]
3 years ago
14

Mercury turns to a vapor at 629.88 K. How much heat is lost when 75.0 g of mercury vapor at 650 K condenses to a liquid at 297 K

?
Chemistry
1 answer:
notsponge [240]3 years ago
4 0

Answer:

- 3706.5 J.

Explanation:

The heat lost by the copper can be calculated using the formula:

Q = m.C.ΔT, where,

Q is the amount of heat lost by the mercury,

m is the mass of the copper <em>(m = 75.0 g)</em>,

C is the specific heat of Hg <em>(C = 0.140 J/g.°C)</em>,

ΔT is the temperature difference (the final temperature - the initial temperature<em> (ΔT = (297 K - 273) °C - (650 K - 273) °C = - 353 °C)</em>.

∴ The amount of heat lost by the mercury Q = m.C.ΔT = (75.0 g) (0.140 J/g.°C) (- 353 °C) = - 3706.5 J.

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All compounds are molecules but not all molecules are compounds. Explain this statement.
Elis [28]
All compounds are molecules because a molecule is 2 or more substances/elements combined and a compound is 2 or more elements combined. But not all molecules are elements because some molecules are just combined substances with no elements combined at all.
5 0
3 years ago
Do subatomic particles have mass
katovenus [111]

Answer:

Yes

Explanation:

Masses for the three subatomic particles can be expressed in amu (atomic mass units) or grams. For simplicity, we will use the amu unit for the three subatomics. Both neutrons and protons are assigned as having masses of 1 amu each.

5 0
3 years ago
How many moles of CCI are there in 78.2 g of CCI.?
vaieri [72.5K]

Answer:

0.508 mole

Explanation:

NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.

The number of mole present in 78.2 g of CCl₄ can be obtained as follow:

Mass of CCl₄ = 78.2 g

Molar mass of CCl₄ = 12 + (35.5×4)

= 12 + 142

= 154 g/mol

Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 78.2 / 154

Mole of CCl₄ = 0.508 mole

Therefore, 0.508 mole is present in 78.2 g of CCl₄

6 0
2 years ago
Vinegar contains carbon, hydrogen, and oxygen with percent masses of 40.01% C, 6.70% H, and 53.29% O, respectively. Determine th
kobusy [5.1K]

The empirical formula is = C2H4O2

Molecular formula=C2H4O2

<h3>Calculation of Molecular formula and empirical formula:-</h3>

Vinegar has three elements:

oxygen = 53.29%,

hydrogen = 6.70%,

and carbon = 40.01%.

We can create an equation for the total mass of vinegar with 'a' carbon atom,' b' hydrogen atom, and 'c' oxygen atoms using the molar masses of C, H, and O.

12*a + 1*b + 16*c = 60

We also know that C makes up 24 g/mol, or 40.01 percent, of the overall mass of 60 g/mol.

The formula contains two C atoms because each C atom has a molecular mass of 12 g/mol. You may determine that the formula contains 4 H and 2 O atoms by using the same reasoning for H and O.

The empirical formula is = C2H4O2

Molecular formula= (C2H4O2)n

(4 x 12 + 1 x 4 + 16 x 2)n = 60

(84)n = 60

n=60/84

n=0.71=1

Molecular formula=C2H4O2

Learn more about Molecular and empirical formulas here:-

brainly.com/question/9207476

#SPJ4

3 0
2 years ago
Name the compound mg3cl2 is it magnesium chloride?
Scilla [17]
No 
Magnesium Chloride is MgCl2 

The method I use to name ionic compounds is 'swap and drop' 

Mg oxidation number is +2 and Cl oxidation number is -1
Mg^2+         Cl^-1  
'swap'
Mg^1           Cl^2 
'drop' 
MgCl2
 
7 0
3 years ago
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