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3 years ago

How many Cl- ions are there in 400.5 grams of AlCl3?

Chemistry

2 answers:

den301095 [7]3 years ago

6 0

Answer:

The answer to your question is letter A

Explanation:

Process

1.- Calculate the molecular mass of AlCl₃

Al = 1 x 27 = 27

Cl = 3 x 35.5 = 106.5

AlCl₃ = 27 + 106.5 = 133.5

2.- Find the number of ions of Cl using proportions

133.5 grams of AlCl₃ ------------- 3 ions of Chlorine

400.5 grams of AlCl₃ ------------ x

x = (400.5 x 3) / 133.5

x = 9

ankoles [38]3 years ago

4 0

Answer:

Explanation:

the answer is d because when you solve it's d

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A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.74 g of water at 52.2 oC in an insulated container. clead = 0.128

QveST [7]

Answer:

Explanation:

Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):

$DH_{lead}=-DH_{water}$

Now, by stating the heat capacity definition:

$m_{Pb}C_{Pb}*(T_{eq}-T_{lead}=-m_{H_2O}C_{H_2O}*(T_{eq}-T_{H_2O})\\$

Solving for the equilibrium temperature:

$T_{eq}=\frac{m_{Pb}C_{Pb}T_{Pb}+m_{H_2O}C_{H_2O}T_{H_2O}}{m_{Pb}C_{Pb}+m_{H_2O}C_{H_2O}} \\\\T_{eq}=\frac{2.04g*0.128J/(g^oC)*10.8^oC+7.74g*4.18J/(g^oC)*52.2^oC}{2.04g*0.128J/(g^oC)+7.74g*4.18J/(g^oC)} \\\\T_{eq}=51.87^oC$

Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.

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3 years ago

A sample of a given compound contains 13.18g of carbon and 3.32g of hydrogen. What is the percent composition of the compound?

GarryVolchara [31]

The percent composition of the compound is 79.87 % of carbon and 20.12% of hydrogen

Explanation:

Given:

mass of carbon = 13.18 grams

mass of hydrogen = 3.32 grams

percent composition of compound =?

From the given data total mass of the compound is calculated

13.8 + 3.32

= 16.5 grams

The individual percentage of hydrogen and carbon will be calculated as:

percent composition = $\frac{individual mass of the element}{total mass of the compound}$ x 100

For carbon,

$\frac{13.18}{16.5}$ x 100

percent composition of carbon = 79.87 % of carbon.

for hydrogen:

$\frac{3.32}{16.5}$

= 20.12 % of hydrogen

In the compound given 79.87 % of carbon and 20.12% of hydrogen is present.

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3 years ago