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mario62 [17]
3 years ago
7

There are three questions for this problem Please answer all three need help!!!

Mathematics
1 answer:
Vlad [161]3 years ago
8 0
Yes what’s your question
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Find the distance between the points (-4,5), (-12,5)
posledela

Answer:

d = 8

Step-by-step explanation:

For:

(X1, Y1) = (-4, 5)

(X2, Y2) = (-12, 5)

Distance Equation Solution:

d=(−12−(−4))2+(5−5)2−−−−−−−−−−−−−−−−−−−−√

d=(−8)2+(0)2−−−−−−−−−−√

d=64+0−−−−−√

d=6–√4

d=8

Therefore, the distance between (-4,5), (-12,5) is 8.

5 0
2 years ago
4-2(x+7)=3(x+5) solve the equation
Ilya [14]

Answer:

-5

Step-by-step explanation:

7 0
3 years ago
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Function is defined by f(x) = x2 - 4x + 8. The graph of function g is shown.
xenn [34]

Answer:5

Step-by-step explanation:

couldn’t tell ya g

3 0
3 years ago
Maria's height while jumping on a a trampoline can be modeled by the equation h=-16t^2+18t+5. Where t=time in seconds and h=heig
Vadim26 [7]

Answer:

10.06 ft

Step-by-step explanation:

Maria's maximum height will occur when her velocity reaches zero (0). This means that she has stopped ascending and is about to begin descent.

The equation for the height reached by Maria on the trampoline is given as:

h=-16t^2+18t+5

To find her maximum height, we first have to find the time it will take her to get to that height and corresponding velocity (zero).

Her velocity can be found by differentiating her height i.e. dh/dt:

v = \frac{dh}{dt} = -32t + 18

Therefore, when v = 0:

0 = -32t+ 18\\\\=> 32t= 18\\\\t = 18 / 32 = 0.5625 secs

It takes her 0.5625 seconds to get to her maximum height.

Therefore, her height at that time (0.5625 seconds) is:

h=-16(0.5625)^2+18(0.5625)+5\\\\h = -16 * (0.3164) + 10.125+5\\\\h = -5.0624 + 15.125\\\\h = 10.06 ft

Therefore, her maximum height is 10.06 ft.

3 0
3 years ago
These box plots show daily low temperatures for a sample of days in two
9966 [12]

Answer:

<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>

<u>IQR for town B, 10.</u>

Step-by-step explanation:

IQR = Q₃ - Q₁

For the town A:

Q₃ = 40  and Q₁ = 20

IQR of town A = 40 - 20 = 20

For the town B:

Q₃ = 30   and Q₁ = 20

IQR of town A = 30 - 20 = 10

Check the given options:

The most statement is appropriate comparison of the spreads is B

<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>

<u>IQR for town B, 10.</u>

<u />

6 0
3 years ago
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