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mario62 [17]
4 years ago
7

There are three questions for this problem Please answer all three need help!!!

Mathematics
1 answer:
Vlad [161]4 years ago
8 0
Yes what’s your question
You might be interested in
Thank you in advance for your help!
Lelechka [254]
I appreciate it too , I had a major problem solving that one.
5 0
4 years ago
What are the solutions of x^2 - 2x + 10 = 0?<br><br> ​
dybincka [34]

Answer:

C. x = 1 + 3i or x = 1 - 3i

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Roots: √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

x² - 2x + 10 = 0

<u>Step 2: Identify Variables</u>

a = 1

b = -2

c = 10

<u>Step 3: Find roots</u>

  1. Substitute [Quad Formula]:                    x=\frac{2\pm\sqrt{(-2)^2-4(1)(10)} }{2(1)}
  2. Exponents:                                              x=\frac{2\pm\sqrt{4-4(1)(10)} }{2(1)}
  3. Multiply:                                                   x=\frac{2\pm\sqrt{4-40} }{2}
  4. Subtract:                                                  x=\frac{2\pm\sqrt{-36} }{2}
  5. Factor:                                                     x=\frac{2\pm\sqrt{-1} \sqrt{36} }{2}
  6. Simplify:                                                   x=\frac{2\pm6i }{2}
  7. Factor:                                                     x=\frac{2(1\pm3i) }{2}
  8. Divide:                                                     x=1\pm3i
5 0
3 years ago
How many grams of water would require 4000 joules of heat to raise its temperature from
serious [3.7K]

Answer: 27.33 g water

Step-by-step explanation:

For this problem, we will need to use the equation for heat: q=mCΔT. Since we are given heat, change in temperature, and specific heat, all we have to do is plug them in to find grams.

4000J=m(4.181J/g°C)(100-65°C)              [find change in temperature]

4000J=m(4.181J/g°C)(35°C)    [divide both sides by specific heat and change in temperature]

m=27.33 g

7 0
3 years ago
Three equivalent ratios for each ratio.<br><br> 18/6 ___<br><br> 5/45___<br><br> 3/5___
Nana76 [90]
9:3     3:1      6:2

1:9   2:18      4:36

6:10   12:20  24:40
7 0
3 years ago
Helpppp Plsssss Asap!! Show your work!! <br><br>Thanks!! ​
Vera_Pavlovna [14]

Answer:

the answer is C

used graphing calculator

Hope This Helped!     Have A Nice Day!!

8 0
3 years ago
Read 2 more answers
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