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dlinn [17]
3 years ago
6

Write the equation of the line that is parallel to y=4x-1 and passes through the point (4.9)

Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0

9514 1404 393

Answer:

  y = 4x -7

Step-by-step explanation:

Rearranging the slope-intercept for equation, we can find the intercept:

  y = mx +b

  y -mx = b . . . . . subtract mx

We know the slope of the parallel line is the same as that of the given line (m=4), so we only need to find 'b'.

  b = 9 -4(4) = -7

The desired equation is ...

  y = mx +b

  y = 4x -7

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Kyle mixes 45 grams of popcorn with 15 grams of powdered cheese. How much popcorn does Kylebuse per gram of cheese?
nekit [7.7K]

Answer:

B

Step-by-step explanation:

45 grams of popcorn/15 grams of cheese = 3 grams of popcorn per 1 gram of cheese

7 0
3 years ago
How do you solve this problem.
Nat2105 [25]

Answer:

8 were yoused  because 8 times 3 =24 so if you subtract you get 8

Step-by-step explanation:

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3 years ago
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3h - j when h = 8 and j = 11<br> plzzz help
AURORKA [14]

Answer:

13

Step-by-step explanation:

3h - j

3(8) - 11

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8 0
3 years ago
In Angkor, Cambodia’s ancient city, a clever/A
stealth61 [152]

There is an error in clever.

<h3>What is the history of Angkor?</h3>

A dynasty of Khmer monarchs oversaw one of the biggest, wealthiest, and most advanced kingdoms in Southeast Asia's history from the city of Angkor, which served as the country's capital. The kings of Angkor ruled over a region that stretched from the tip of the Indochinese Peninsula northward to modern-day Yunnan province, China, and from Vietnam westward toward the Bay of Bengal from the last decade of the 9th century, when King Yashovarman I made Angkor his home, until the early years of the 13th century. These kings built a number of enormous structures throughout this time period to exalt themselves, their gods, and their capital city. They did this by using the enormous labour and financial resources at their disposal.

To learn more about Angkor, Visit:

brainly.com/question/486956

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7 0
1 year ago
If you answer God will bless you:
VashaNatasha [74]

Answer:

600 m³

Step-by-step explanation:

Given:

  • length of swimming pool = 30 m
  • width of swimming pool = 10 m
  • depth at deep end = 3 m
  • depth at shallow end = 1 m

To find the volume of the water in the pool, find the area of a cross section (see attached image) and multiply it by the width of the pool.

<u>Area of cross section</u>

= area of rectangle - area of triangle

= (3 × 30) - [1/2 × 30 × (3 - 1)]

= 90 - 30

= 60 m²

<u>Volume of pool</u>

= area of cross section × width

= 60 × 10

= 600 m³

6 0
2 years ago
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