The answer is thanks a lot
Answer:
E. P(W | H)
Step-by-step explanation:
What each of these probabilities mean:
P(H): Probability of the game being at home
P(W): Probability of the game being a win.
P(H and W): Probability of the game being at home and being a win.
P(H|W): Probability of a win being at home.
P(W|H): Probability of winning a home game.
Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?
This is the probability of winning a home game. So the answer is:
E. P(W | H)
The straight line distance from the starting point is 41 miles.
<u>Explanation:</u>
Given:
Distance covered towards north, n = 9 miles
Distance covered towards east, e = 40 miles
Distance from the origin to the end, x = ?
If we imagine this, then the route forms a right angle triangle
where,
n is the height
e is the base
x is the hypotenuse
Using pythagoras theorm:
(x)² = (n)² + (e)²
(x)² = (9)² + (40)²
(x)² = 1681
x = 41 miles
Therefore, the straight line distance from the starting point is 41 miles.
Since we don't know how much students there is going to be, let's assume it's x. 367x+1500=16600. 16600-1500=15100. We have to isolate x by itself so 15100/367 which equals 41.14etc And round it to 41 since there can't be a decimal of a student. Hope this helped.
