Answer is: molecular formula is C₆H₈O₆.
n(C) = m(C) ÷ M(C).
n(C) = 40,5 g ÷ 12 g/mol.
n(C) = 3,375 mol.
n(H) = m(H) ÷ M(H).
n(H) = 4,5 g ÷ 1 g/mol.
n(H) = 4,5 mol.
n(O) = m(O) ÷ M(O).
n(O) = 55 g ÷ 16 g/mol.
n(O) = 3,4 mol.
n(C) : n(H) : n(O) = 3,375 mol : 4,5 mol : 3,4 mol / :3,375.
n(C) : n(H) : n(O) = 1 : 1,33 : 1.
n(C) : n(H) : n(O) = 3 : 4 : 3.
M(C₃H₄O₃) = 88 g/mol · 2 = 176 g/mol.
Answer:
Molarity = 0.08 M
Explanation:
Given data:
Mass of sodium carbonate = 10.6 g
Volume of water = 1.25 L
Molarity of solution = ?
Solution:
First of all we will calculate the moles of solute.
Number of moles = mass/molar mass
Number of moles = 10.6 g/ 106 g/mol
Number of moles = 0.1 mol
Formula:
Molarity = moles of solute / volume of solution in L
Now we will put the values in formula.
Molarity = 0.1 mol / 1.25 L
Molarity = 0.08 M
<u>Answer:</u> The volume of concentrated hydrochloric acid required is 16.53 mL
<u>Explanation:</u>
To calculate the volume of concentrated solution, we use the equation:
where,
are the molarity and volume of the concentrated solution
are the molarity and volume of diluted solution
We are given:
Conversion factor: 1 L = 1000 mL
Putting values in above equation, we get:
Hence, the volume of concentrated hydrochloric acid required is 16.53 mL
Moles of ca3(po4)2 = 23.7 / 310.17 = 0.076
moles of (PO4)3- = 0.076 x 2 = 0.152
now, no. of ions = 0.152 x 6.022 x 10^{23}
= 9.2 x 10^{22}
