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nata0808 [166]
3 years ago
10

Why are mole ratios important to stoichiometry calculations?

Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0
<span>Mole ratios are important to stoichiometric calculations because they bridge the gap when we have to convert between the mass of one substance and the mass of another.</span>
You might be interested in
What quantum numbers specify a 5p orbital?
mezya [45]

n = 5

l = 0,1,2,3,4

ml = -4,-3,-2,-1,0,1,2,3,4,

ms = +1/2 and -1/2

8 0
3 years ago
How many moles of sulfuric acid (H2SO4) are present in 500.0 mL of 0.15 M H2SO4 solution?
galben [10]

Answer:

Number of moles = 0.075 mol

Explanation:

Volume = 500.0 mL = 0.5 (Converting to L by dividing by 1000)

Molarity = 0.15 M

Number of moles = ?

The relationship between the quantities is given as;

Molarity  = Number of moles / Volume

Number of moles = Molarity * Volume

Number of moles = 0.15  * 0.5

Number of moles = 0.075 mol

7 0
3 years ago
Calculate the molar solubility of ca(io3)2 in each solution below. the ksp of calcium iodate is7.1 × 10−7.
e-lub [12.9K]
In order to find the answer, use an ICE chart:

Ca(IO3)2...Ca2+......IO3- 
<span>some.......0..........0 </span>
<span>less.......+x......+2x </span>
<span>less........x.........2x 
</span>
<span>Ca(IO₃)₂ ⇄ Ca⁺² + 2 IO⁻³
</span>
K sp = [Ca⁺²][IO₃⁻]²
K sp = (x) (2 x)² = 4 x³
7.1 x 10⁻⁷ = 4 x³
<span>x = molar solubility = 5.6 x 10</span>⁻³ M

The answer is 5.6 x 10 ^ 3 M. (molar solubility)
5 0
3 years ago
Read 2 more answers
At 46°C a sample of ammonia gas exerts a pressure of 5.3 atm. What is the pressure when the volume of the gas is reduced to one-
snow_lady [41]

Hello there!

As you may know, pressure and volume have an inverse relationship. This means that as pressure increases, volume decreases (and as volume increases, pressure decreases).

In this problem, the volume of the gas is reduced to 0.250 its original value. This means that the pressure should be higher than it was originally.

We can use Boyle's Law to solve this problem, seeing that temperature is kept constant.

P1V1 = P2V2

Let's rearrange this equation to isolate the variable we need, P2.

P1V1

-------   = P2

 V2

That's better! Now that we have that down, let's plug in the numbers we were given.

(5.3atm) * (V1)

-------------------- = P2

0.25(V1)

We can get rid of V1, as the number would be equal to 1 (anything divided by itself is equal to 1).

5.3atm

---------- = 21.2 atm

0.25L

Now, while the number is significantly higher, this is quite reasonable.

Let's plug it in and see if we get what we should:

5.3(V1) = (0.25V1)(21.2)

--------

0.25V1

21.2 atm = 21.2 atm

Seems right to me!

Feel free to comment if you need any more help. :)

5 0
4 years ago
my tens digit is 2 more than my hundreds digit and my ones digit is 1 more than my tens digit. my Hundreds digit is 5. what numb
Marta_Voda [28]
578 is definitely the answer
6 0
3 years ago
Read 2 more answers
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