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andreyandreev [35.5K]
3 years ago
7

In a chemical reaction, 36 grams of hydrochloric acid reacts with 40 grams of sodium hydroxide to produce sodium chloride and wa

ter. Which statement is correct?
The mass of water formed is 76 grams.
The mass of sodium chloride formed is 76 grams.
The mass of water formed is greater than 76 grams.
The mass of sodium chloride formed is less than 76 grams.
Chemistry
2 answers:
Blizzard [7]3 years ago
5 0
The mass of sodium chloride is less then 76g. Explanation: NaOH is limiting reagent (1 mol), HCl is excessive reagent (>1 mol). NaCl will be 1 mol (equal to NaOH) in the reaction: HCl + NaOH -> NaCl + H2O. Mass of NaCl will be: 1 mol * 58.5 g/mol = 58.5 g < 76 g.
Elena L [17]3 years ago
3 0
The answer is <span>The mass of sodium chloride formed is less than 76 grams.
</span>
Remember Mass is never gained or loss in any chemical reactions

So,

hydrochloric acid  + sodium hydroxide  =>  <span>sodium chloride + water
                          Total 76 gram                         Total will also 76 gram

In this case, the mass of sodium chloride will be less than 76 gram because we need to take out the mass of the water.

</span>
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Sadiq repeated the experiment by adding sulphuric acid to magnesium carbonate. Write the word equation for this reaction below:
anygoal [31]

Answer:

Sulphuric acid + Magnesium Carbonate → Magnesium sulphate + carbon dioxide + water

Explanation:

Sulphuric acid + Magnesium Carbonate

The products are;

Magnesium sulphate, carbon dioxide and water

MgCO3 (s) + H2SO4 (aq) → MgSO4 (aq) + CO2 (g) + H2O (l)

Word Equation;

Sulphuric acid + Magnesium Carbonate → Magnesium sulphate + carbon dioxide + water

7 0
3 years ago
A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33
ANEK [815]

Explanation:

The given data is as follows.

     Vapour pressure of pure CCl_{4} = 33.85 Torr

         Temperature = 298 K

      Mole fraction of Br_{2} = 122.36 torr

Therefore, calculate the vapor pressure of Br_{2} as follows.      

     Vapour pressure of Br_{2} = mole fraction of Br_{2} x K of Br_{2}

                                    = 0.050 x 122.36 Torr

                                   = 6.118 Torr

So, vapor pressure of Br_{2} is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

     Vapour pressure of CCl_{4} = mole fraction of CCl_{4} x Pressure of CCl_{4}

                                     = (1 - 0.050) × 33.85 Torr

                                     = 32.1575 Torr

So, vapor pressure of CCl_{4} is 32.1575 Torr  .

Hence, the total pressure will be as follows.

                         = 6.118 Torr + 32.1575 Torr

                         = 38.2755 Torr

Therefore, composition of CCl_{4} = \frac{32.1575 Torr}{38.2755 Torr}

                         = 0.8405

Composition of CCl_{4} is 0.8405 .

And, composition of Br_{2} = \frac{6.118 Torr}{38.2755 Torr}

                                                  = 0.1598

Composition of Br_{2} is 0.1598 .

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3 years ago
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bija089 [108]

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