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Sindrei [870]
3 years ago
11

A molecular _________

Chemistry
1 answer:
Butoxors [25]3 years ago
4 0

Answer:

A molecular formulae________

will tell you how many and what

kinds of atoms are in a molecule, but not how they are

arranged.

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Which indicator is yellow in a solution with a pH of 9.8?
Vlada [557]
It's the Methyl Orange. 
at about 4.4 pH, it changes from red to Yellow, to indicate an acid solution.
This pH indicator is normally used in titration of acids.

Hope this Helps :)
8 0
3 years ago
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The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon
xenn [34]

<u>Answer:</u> The percent composition of Fe_3O_4 in taconite is 37.6 %.

<u>Explanation:</u>

We are given:

Mass of taconite pellets = 1 ton = 907185 g      (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g    (Conversion factor:  1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of Fe_3O_4 = 231.53 g/mol

1 mole of Fe_3O_4 contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of Fe_3O_4

So, 247212 grams of iron will be produced from = \frac{231.53}{167.55}\times 247212=341611.43g of Fe_3O_4

To calculate the percentage of Fe_3O_4 in taconite, we use the equation:

\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100

Mass of taconite = 907185 g

Mass of Fe_3O_4 = 341611.43 g

Putting values in above equation, we get:

\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%

Hence, the percent composition of Fe_3O_4 in taconite is 37.6 %.

8 0
3 years ago
Look at the two thermometers.
salantis [7]

Answer:

Thermometer A, because it measures accurately to the tenths digit.

3 0
3 years ago
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Nitrifying bacteria participate in the nitrogen cycle mainly by
Brilliant_brown [7]
Hello, here’s the answer to your question. Converting ammonia to nitrate, which is absorbed by plants
6 0
3 years ago
you are given 500 mL of a 5M stock solution of ammonium chloride but for your experiment, you only need 100 mL of a 0.65M soluti
mafiozo [28]

Answer:

13ml

Explanation:

  1. to prepare dis solution first you need a volumetric flask of 100ml calibrated .
  2. using dilution formulae u will need 13ml from the stock
  3. measure 13ml of the 5M stock of the 500ml
  4. then drop it into the 100ml calibrated flask
  5. then add water till it reach d mark and you shake thoroughly
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3 years ago
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