Answer: 2.9 m/s
Explanation:
The frequency of the beat is 4 Hz
The relative Doppler frequency is 235 + 4 = 239 Hz
We would be solving this question, using the formula for Doppler's effect
f(d) = f(v+vr)/(v-vs), where
F = 235 Hz
F(d) = 239 Hz
v = 344 m/s and vr = vs
239 = 235 (344 + vr) / (344 - vr)
239 ( 344 - vr) = 235 (344 + vr)
82216 - 239 vr = 80849 + 235 vr
82216 - 80849 = 235 vr + 239 vr
1376 = 474 vr
vr = 1376/474
vr = 2.9 m/s
Thus the speed the platform should move is 2.9 m/s
Answer:
North of west
Explanation:
Given
40,000-ton luxury line traveling 20 knots towards west and
60,000 ton freighter traveling towards North with 10 knots
suppose v is the common velocity after collision
conserving momentum in west direction

suppose the final velocity makes \theta angle with x axis

Conserving Momentum in North direction


divide 1 and 2


so search in the area
North of west to find the ship
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.