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algol13
3 years ago
9

Given that XeF4 reacts with water to form explosive XeO3, chemists would not handle it near water. However, why would you still

not want to work with it on the lab bench, even if there was apparently no water around?
Chemistry
1 answer:
Svetlanka [38]3 years ago
8 0
Bro that’s so cool man have a good day
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How many moles are in 13.5g of calcium?
antiseptic1488 [7]

Answer:

=0.337mol Ca this is the correct answer :)

3 0
2 years ago
If a 500 ml sample of water contains 2.6 x 10-6 g of iron, what is the concentration of iron in ppb?
Anastasy [175]

The concentration of iron in ppb is 5.2 ppb

In atmospheric chemistry, PPM( parts per million) and PPB( parts per billion) units are used to express the concentration of gases. PPB stands for parts per billion, while PPM stands for parts of gas per million parts of air.

2.6 × 10⁻⁶ grams of iron in 500 ml of water.

Now, converting milliliter into liter:

500 mL = 500 mL × ( 1L / 1000 mL ) = 0.5 L

Now for ppm, mass must be in mg.

2.6 × 10⁻⁶ grams = 2.6 × 10⁻⁶ grams × ( 1000 mg / 1 grams ) = 2.6 × 10⁻³ mg

Then, the concentration of iron in ppm will be:

2.6 × 10⁻³ mg / 0.5 L = 5.2 × 10⁻³ ppm

Now, 1 ppm = 1000 ppb

Therefore,

5.2 × 10⁻³ ppm × 10³ = 5.2 ppb

Learn more about concentration here:

brainly.com/question/17206790#:~:text=15%20people%20helped-,Answer%3A,either%20solvent%20or%20total%20solution.

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8 0
8 months ago
A gas at 45 o C occupies 5.22 L. At what temperature will the volume be 6.87 L?
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2 years ago
A mixture initially contains AA, BB, and CC in the following concentrations: [A][A]A_1 = 0.550 MM , [B][B]B_1 = 1.40 MM , and [C
Alex787 [66]

Answer:

The value of the equilibrium constant KC is 1.244

Explanation:

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.550 M, [B] = 1.40 M, and [C] = 0.600 M. The following reaction occurs and equilibrium is established: A+2B<->C

At equilibrium, [A] = 0.430 M and [C] = 0.720 M. Calculate the value of the equilibrium constant, Kc

Step 1: The balanced equation

A+2B<->C

Step 2: The initial concentrations

[A] = 0.550 M

[B]= 1.40 M

[C] = 0.600 M

Step 3: The concentraions at equilibrium

[A] = 0.550 -X = 0.430 M

[B]= 1.40 -2X M

[C] = 0.600 + X = 0.720 M

X = 0.120 M

[A] = 0.550 - 0.120 = 0.430 M

[B]= 1.40 -2*0.120 =  1.16 M

[C] = 0.600 + 0.120 = 0.720 M

Step 4: Calculate Kc

Kc = [C] / [A][B]²

Kc = 0.720 / (0.430*1.16²)

Kc = 1.244

The value of the equilibrium constant KC is 1.244

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3 years ago
A science fair volcano bubbles and fizzes. what is taking place?
vaieri [72.5K]
Answer is B. gas formation
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