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AlladinOne [14]
3 years ago
6

Sandstone is a sedimentary rock which of the following characteristics would you look for in a piece of sand stone

Chemistry
1 answer:
vaieri [72.5K]3 years ago
3 0
Sandstone is a sedimentary rock. The characteristics that you would <span>look for in a piece of sand stone are B. rock layers have small rocks or fossils in them. </span>
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What is produced at each electrode in the electrolysis of agf(aq)?
Rzqust [24]
AgF consists of Ag+ and F- ions, which are fully dissociated in aqueous solution. When solving electrolysis problems, it is important to remember that water itself may also be a subject to electrolysis. Therefore, determining which species is oxidized and which species is reduced depends on selecting the processes that are the most energetically favorable. The most preferred reduction reaction will be  Ag+ + e- = Ag (Emf=0.7996 V) which will occur at the cathode, on the other hand, the most favorable oxidation reaction will be
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8 0
2 years ago
What is the answer for chemestry when it says 1.204 times 10^24
Sphinxa [80]

Answer: This is called moles

Explanation:  This is described to be the number of molecules, atoms or ions in a substance :)

6 0
3 years ago
How many molecules are there in 3 moles of aluminum chloride ?
Svetradugi [14.3K]

there are 4 atoms in aluminum chloride

6 0
2 years ago
Find the number of chromium ions in 3.5 mol of chromium ions.
Ray Of Light [21]

Answer:

2.1 x 10^24 Cr ions

Explanation:

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3 0
2 years ago
Estimate your de Broglie wavelength when you are running. (For this problem use h = 10^−34 in SI units and 1 lb is equivalent to
AlekseyPX

Answer:

A. your running speed 1.5 m/s

B. your mass 70 kg

C. your de Broglie wavelength 6.32x10^{-36}m

Explanation:

Hello there!

In this case, since the equation for the calculation of the Broglie wavelength is:

\lambda =\frac{h}{m*v}

We can assume a running speed of about 1.5 m/s and a mass of 70 kg, so the resulting Broglie wavelength is:

\lambda =\frac{6.626x10^{-34}kg\frac{m}{s} }{70kg*1.5\frac{m}{s} }\\\\\lambda =6.32x10^-36m

Best regards!

7 0
3 years ago
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