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Marina CMI [18]
3 years ago
14

58 is what percent of 40

Mathematics
2 answers:
Oksana_A [137]3 years ago
4 0

58÷40×100 which will give you 145 as the answer.

8090 [49]3 years ago
3 0

Answer: 145

Step-by-step explanation:r 58÷40×100 which will give you 145 as the answer.

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If 30 buses can carry 1,500 people, how many people can 5 buses carry? A 200 © 500 B 250 D 750​
maksim [4K]

Answer:

\boxed {\boxed {\sf 250 \ people}}

Step-by-step explanation:

Let's set up a proportion using the following setup.

\frac {buses}{people}=\frac {buses}{people}

We know 30 buses can carry 1,500 people.

\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}

We don't know how many people 5 buses can carry, so we say 5 buses carry x people.

\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}

\frac {30 }{1500 }=\frac {5 }{x }

Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.

30*x=1500*5\\30x=7500

Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.

30x/30=7500\\x=250

5 buses can carry 250 people.

7 0
3 years ago
Find the Domain: <br> {(-5, 3), (-1,0), (3, -4), (-1, 2)}
Marrrta [24]

Answer:

(-1,2) is domain

Step-by-step explanation:

5 0
3 years ago
Find the x and y intercepts of -7xt6y=5
iren2701 [21]
-7x + 6y =5
x intercept. y=0
-7(x) + 6(0)=5
x=-5/7

y intercept, x=0
-7(0)+6(y) =5
y=5/6
3 0
2 years ago
9. Zuleyka compró una bicicleta por $149. Pagó un pronto de $50. Si pagó $9
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Answer:

h s m s dhoni bold sin men farhan akhtar ne

5 0
2 years ago
A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

C-2=\frac{1}{11}*(C+D-2)...(1)

We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)

\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)

Multiplying both sides of our equation by 7, we will get,

7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)

C+D-10=\frac{7}{11}*(C+D-2)  

Multiplying both sides of our equation by 11, we will get,

11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

11*(C+D-10)=7*(C+D-2)

11C+11D-110=7C+7D-14

11C-7C+11D-7D=-14+110  

4C+4D=96

4(C+D)=96  

(C+D)=\frac{96}{4}

(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

3 0
3 years ago
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