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3 years ago

Which sentence describes the bond formed between two identical atoms?

Chemistry

2 answers:

kicyunya [14]3 years ago

5 0

Answer:

B. The electrons involved in the bond are shared equally between the

atoms.

- A P E X

Lilit [14]3 years ago

3 0

The best answer is C

Since identical atoms would have the same electronegativity, thus making its electronegativity difference close to zero, if not equal to zero (O), making the bond between the two to be covalent. Thus, a chemical bond formed between two identical atoms is a covalent bond.

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A 0.1025-g sample of copper metal is dissolved in 35 ml of concentrated hno3 to form cu2 ions and then water is added to make a

GalinKa [24]

Molarity is defined as number of moles of solute in 1 L of solution.

Here, 0.1025 g of Cu is reacted with 35 mL of HNO_{3} to produced Cu^{2+} ions.

The balanced reaction will be as follows:

Cu+3HNO_{3}\rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O

From the above reaction, 1 mole of Cu produces 1 mole of Cu^{2+}, convert the mass of Cu into number of moles as follows:

n=\frac{m}{M}

molar mass of Cu is 63.55 g/mol thus,

n=\frac{0.1025 g}{63.55 g/mol}=0.0016 mol

Now, total molarity of solution, after addition of water is 200 mL or 0.2 L can be calculated as follows:

M=\frac{n}{V}=\frac{0.0016 mol}{0.2 L}=0.008 mol/L=0.008 M

Thus, molarity of Cu^{2+} is 0.008 M.

7 0

3 years ago

The pressure exerted on 240. Ml sample of hydrogen at constant temperature is increased from .428 ATM to .724 ATM what will the

Flauer [41]

P1v1=p2v2
v2=p1v1/p2
v2=428x240/724
v2=141.87

4 0

4 years ago

Calculate the concentration (M) of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to

Luda [366]

The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:

$m_1v_1 = m_2v_2$

Where $m_1$ is the molarity before dilution, $v_1$ is the volume before dilution, $m_2$ is the molarity after dilution, and $v_2$ is the volume after dilution.

In this case, $m_1$ = 0.774 M, $v_1$ = 10.0 mL, $v_2$ = 100 mL.

$m_2$ = $m_1v_1/v_2$

= 0.774 x 10/100

= 0.0774 M

Thus, the new concentration of the sodium sulfide solution would be 0.0774 M.

Mole of the final solution: 0.0774 x 0.1 = 0.00774 mol

Sodium sulfide formula = $Na_2S$ ---> $2Na^+ + S^{2-$

Equivalent mole of sodium ion = 0.00774 x 2

= 0.01548 mol

The concentration of sodium ions = mol/volume

= 0.01548/0.1

= 0.1548 M

In other words, the concentration of the sodium ions in the diluted solution would be 0.1548 M.

More on dilution can be found here: brainly.com/question/21323871

#SPJ1

6 0

1 year ago

A 7.337 gram sample of chromium is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 9.595 g. Dete

Thepotemich [5.8K]

<h3>Answer:</h3>

Empirical formula is CrO

<h3>Explanation:</h3>

<u>We are given;</u>

Mass of sample of Chromium as 7.337 gram
Mass of the metal oxide formed as 9.595 g

We are required to determine the empirical formula of the metal oxide.

<h3>Step 1 ; Determine the mass of oxygen used </h3>

Mass of oxygen = Mass of the metal oxide - mass of the metal

= 9.595 g - 7.337 g

= 2.258 g

<h3>Step 2: Determine the moles of chromium and oxygen</h3>

Moles of chromium metal

Molar mass of chromium = 51.996 g/mol

Moles of Chromium = 7.337 g ÷ 51.996 g/mol

= 0.141 moles

Moles of oxygen

Molar mass of oxygen = 16.0 g/mol

Moles of Oxygen = 2.258 g ÷ 16.0 g/mol

= 0.141 moles

<h3>Step 3: Determine the simplest mole number ratio of Chromium to Oxygen</h3>

Mole ratio of Chromium to Oxygen

Cr : O

0.141 mol : 0.141 mol

1 : 1

Empirical formula is the simplest whole number ratio of elements in a compound.

Thus the empirical formula of the metal oxide is CrO

6 0

3 years ago

Measurements show that enthalpy of a mixture of gaseous reactants decreases by 228. kJ during a certain chemical reaction, which

Tcecarenko [31]

Total change in energy = Heat produced by system + work done on the system
= 228 - 55
= 173 kJ

Because this energy is released as heat, the reaction is exothermic.

7 0

3 years ago

Read 2 more answers