Answer:
Step-by-step explanation:
When two chords intersect inside the circle, the product of their segments are equal.
BE * ED = AE * EC
x *3x = 4 *3
3x² = 12 {Divide both sides by 3}
x² = 12/3
x² = 4
x = √4
x = 2
-10z+14 would be the simplified answer
Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.
Given:
Ray QS bisects ∠PQR.
m∠PQS = 3x
m∠SQR = 5x-20
To find:
The value of x and m∠PQR
Solution:
Ray QS bisects ∠PQR. So,
The value of x is 10.
Now,
Put x=10,
Therefore, the m∠PQR is 60 degrees.
We have an isosceles triangle and 2 lines that are drawn through some ( any ) point on the base. The both lines are parallel to one of the legs. Then those lines with the legs of the triangle make a parallelogram. We can say that x and y are the sides of the parallelogram. Then: x + y = 5 in. And the perimeter of the parallelogram: P = 2 x + 2 y = 2 * ( x + y ).
P = 2 * 5 =
10 in. The rest is in the attachment.
Answer: The perimeter of the constructed parallelogram is 10 inches.
Answer:
x = 14+
Step-by-step explanation:
If 14 + 14 = 28
Then
28 > 27 is true.
