Answer:
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Step-by-step explanation:
Given that:
Mean = μ = 150
SD = σ = 12
Let x1 be the first data point and x2 the second data point
We have to find the z-scores for both data points
x1 = 135
x2 = 167
So,

And

We have to find area to the left of both points then their difference to find the probability.
So,
Area to the left of z1 = 0.1056
Area to the left of z2 = 0.9207
Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151
Hence,
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Answer: Choice A) 4/5
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Work Shown:
cos^2(theta) + sin^2(theta) = 1
(-3/5)^2 + sin^2(theta) = 1
9/25 + sin^2(theta) = 1
9/25 + sin^2(theta) - 9/25 = 1 - 9/25
sin^2(theta) = 1 - 9/25
sin^2(theta) = 25/25 - 9/25
sin^2(theta) = (25 - 9)/25
sin^2(theta) = 16/25
sqrt[sin^2(theta)] = sqrt[16/25]
sin(theta) = 4/5
The fact that sine is positive in quadrant 2 means that the result is positive.
Answer:
<h2>V = 729</h2>
Step-by-step explanation:
The formula of a volume of a cube with an edge <em>a</em>
<h3>
V = a³</h3>
We have <em>a </em>=<em> </em>9 . Substitute:
<h3>V = 9³ = 9 · 9 · 9 = 729</h3>
Answer:
There are 3478761 ways to select the first 5 numbers
Step-by-step explanation:
As understood from the statement of this problem we assume that it does not matter the order in which the first 5 white balls are selected.
In this case it is a combination.
So, what we want to know is how many ways you can choose 5 white balls out of 55.
Then we use the formula of combinations:

Where you have n elements and choose x from them.
Then we look for:
