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4 years ago

Please help me with this problem, The answer is 192 but how do you solve it??

Mathematics

1 answer:

AnnZ [28]4 years ago

3 0

Answer:

192

Step-by-step explanation:

You can form a rectangle from sides 15 and 3, another rectangle with dimensions 10 and 9, another rectangle with dimensions 6 and 5, and a triangle with sides 9 and 6 (all formed by extending lines inside the figure, don't want to go into detail). Add all the areas and the answer would be 192:

15*3 =45

10*9=90

6*5=30

0.5*9*6=27;

45 + 90 +30 + 27 = 192 units squared

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The owner of a used car lot wants to buy many cars at an auction as he can while not spending more than $20000. If he expects th

AleksAgata [21]

Answer:

Step-by-step explanation:

Given that:

Total maximum amount that the owner wishes to spend = $20000

Average price of each car = $4000

To find:

How many cars that the owner can expect to buy?

Solution:

Total number of cars that the owner can expect to buy can be found by dividing the total money available with the owner with the average price of each car.

i.e.

$\text{Number of cars expected to be bought} = \dfrac{\text{Total money available with the owner}}{\text{Average Price of car}}$

We have the following values as given in the question statement:

Total money available = $20000

Average price of car = $4000

Therefore, the answer is:

$\text{Number of cars expected to be bought} = \dfrac{20000}{4000} = \bold{5}$

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7 0

3 years ago

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Arada [10]

Answer:

23 tables were used that day at lunch.

Step-by-step explanation:

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3 0

3 years ago

A toy manufacturer wants to know how many new toys children buy each year. A sample of 601 children was taken to study their pur

Lilit [14]

Answer:

The confidence interval is 6.6<μ<6.8.

Step-by-step explanation:

We have:

Number of observations = 601

Mean = 6.7

Standard deviation σ = 1.5

The z-score for a 95% confidence interval is 1.96.

The limits of the confidence interval can be calculated as

$X \pm z*\frac{\sigma}{\sqrt{n}}\\\\LL=X-z*\frac{\sigma}{\sqrt{n}}=6.7-1.96*\frac{1.5}{\sqrt{601} } =6.7-0.1199=6.6\\\\UL=X+z*\frac{\sigma}{\sqrt{n}}=6.7+1.96*\frac{1.5}{\sqrt{601} } =6.7+0.1199=6.8$