Unit vector along the direction v = <3,1,-4> is :
So, unit vector opposing the 
is :
so, vector of magnitude 3 units in opposite direction from v is :
Hence, this is the required solution.
Let h(t) represent the height of the projectile after t seconds. If the projectile is being launched from the ground, then h(0)=0, and h(t)=-4.9t²+98t. When the equation is in this form, the maximum height is determined by -98/2(-4.9), or after 10 seconds. Thus
-4.9(100)+98(10)=490 m as the highest point of the projectile
Then, when it hits the ground, h(t)=0, so
0=-4.9t²+98t
98t=4.9t²
4.9t=98
t=20
☺☺☺☺
Answer:
Volume of one Bugle => 462.8 mm³
Volume of 18 Bugles => 8,330.4 mm³
Volume formula for a cone => ⅓πr²h
Step-by-step explanation:
Volume of one bugle = volume of cone (V) = ⅓πr²h
Where,
r = 5.1 mm
h = 17 mm
Volume of one Bugle = ⅓*π*5.1²*17 = 462.8 mm³
Volume of 18 Bugles = 462.8 × 18 = 8,330.4 mm³
Answer:
A
Step-by-step explanation:
