Stirring promotes the reaction by exposing all of the unreacted region of the marble to the acid. Moreover, mixing increases the degree of homogenity within the reaction mixture, meaning the reaction is carried out evenly through out rather than faster in some regions while slower in others.
I Think This Is Right
A saturated is one in which the atoms are linked by single bonds. :)
Answer:
if your title doesn't have enough information, make a list of the key words ... If you are not sure what should be included in each summary sentence, use ... Often you can present the hypothesis and the supporting reasoning in one paragraph. ... Describe specific parts of the procedure or data that contributed to your learning.
Explanation:
The nitrate reduction test identifies whether the given strain of bacteria is able to reduce nitrate to nitrite using anaerobic respiration.
In this test, the solution is incubated after adding the bacteria strain. After the incubation period is over, additional solutions Sulfuric acid (a) and Naphthylamine (b) are added to it.
If the reduction has occurred and the nitrite is present, then the solution gives red color.
If there is no color change, then the solution is tested for the presence of other reduction products like N2 gas , NH3 gas etc. This is done by adding zinc to the solution.
Zinc is able to reduce nitrate to nitrite only. Therefore a color change after the addition of zinc indicates that the bacterial strain was not able to reduce nitrate and nitrates are still present which were reduced by zinc.
If there is no color change, that means the nitrates are absent and the bacteria has reduced nitrate to some other species like N2 or NH3 gas.
Therefore , In the nitrate reduction test, only after the addition of zinc to your 24-hour incubated solutions a and b is there a color change. This indicates that the bacteria was not able to reduce nitrate to nitrite.
Answer:
The answer to your question is: C₁₈ H₂₇ N O₃
Explanation:
Data
Carbon = 70.79 g
Hydrogen = 8.91 g
Nitrogen = 4.58 g
Oxygen = 15.72 g
Process
AT C = 12 g
AT H = 1 g
AT N = 14 g
AT O = 16 g
Carbon
12 g ------------------------ 1 mol
70.79 g ------------------------- x
x = (70.79 x 1) / 12
x = 5.9 mol of C
Hydrogen
1 g ----------------------- 1 mol
8.91 g --------------------- x
x = (8.91 x 1) / 1
x = 8.91 mol of H
Nitrogen
14 g ---------------------- 1 mol
4.58 g ------------------- x
x = (4.58 x 1) / 14
x = 0.33 mol
Oxygen
16 g ------------------------ 1 mol
15.72 g -------------------- x
x = (15.72 x 1)/16
x = 0.98
Divide by the lowest number of moles
Carbon 5.9 / 0.33 = 17.9 ≈ 18
Hydrogen 8.91 / 0.33 = 27
Nitrogen 0.33 / 0.33 = 1
Oxygen 0.98 / 0.33 = 2.9 ≈ 3
C₁₈ H₂₇ N O₃
