Since there is so little information given, I will assume that we are at STP and i can use the conversion factor at STP--->> 22.4 Liters= 1 mol of gas
before we use this conversion, we need to convert the grams to moles using the molar mass of the molecule.
molar mass of Cl₂= 35.5 x 2= 71.0 g/ mol
177.3 g (1 mol/ 71.0 g)= 2.50 mol Cl₂
then we use the conversion to get the volume
2.50 mol Cl₂ (22.4 Liters/ 1 mol)= 55.9 Liters
Answer:
I think C
Explanation:
because hydrogen on the right side only have two while on the left side it have 4
Answer:
Hydrogen: -141 kJ/g
Methane: -55kJ/g
The energy released per gram of hydrogen in its combustion is higher than the energy released per gram of methane in its combustion.
Explanation:
According to the law of conservation of the energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.
Qc + Qb = 0
Qc = -Qb [1]
We can calculate the heat absorbed by the bomb calorimeter using the following expression.
Q = C . ΔT
where,
C is the heat capacity
ΔT is the change in the temperature
<h3>Hydrogen</h3>
Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (14.3°C) = -162 kJ
The heat released per gram of hydrogen is:

<h3>Methane</h3>
Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (7.3°C) = -82 kJ
The heat released per gram of methane is:

It is highly hazardous, it is radioactive
Answer:
I believe the answer is 1m/s²
Explanation:
acceleration= change in speed ÷ time (I hope this is correct)