Question

While in Europe, if you drive 109 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 22.0 mi/gal ? Assume that 1euro=1.26dollars.

Answer 1

Answer:

The amount is $x = 113.3 \ dollars$

Explanation:

From the question we are told that

     The  distance traveled per day is  $l = 109\ km = \frac{109}{1.609} = 67.74 \ mi$

    The  cost of one liter is  $c = 1.10 \ euros/liter = 1.10 * 1.26 = 1.36 \ dollars/liter$

     The car's  gas mileage is  $b = 22.0 \ mi/gal$

Generally the amount of distance covered in one week is evaluated as

      $z = 67.74 * 7$

       $z = 474.18 \ mi$

The  amount of gas used in one week by the car is mathematically represented as  

       $k = \frac{ z}{ b}$

=>    $k = \frac{ 474.18}{ 22}$

=>      $k = 22 \ gal$

converting to liters

          $k = 22 * 3.78541=83.28 \ liters$

Thus the amount spent on gas in one week is  

          $x = k * c$

=>      $x = 83.28 * 1.36$

=>      $x = 113.3 \ dollars$