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3 years ago

10

Which of the following graph(s) is not a function of y? A function generally takes the form f(x) = y. a y = 3 b 4x+7=y c y=x d x

=|y|

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

ummmmmmmmmmmmmmmmmm what graph?????????????

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Architects make scale models of buildings to present their ideas to clients. If an

MaRussiya [10]

The area of the model is 80 square foot

Step-by-step explanation:

Let the area of the house model be 'a'

The scale = 1:50

The area of the house= 4000 square foot

Area of the model =4000/50

a = 80 square foot

The area of the model is 80 square foot

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3 years ago

Which ordered pair is a solution of the equation?<br> -x- 4y = -10

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3 years ago

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160% as a decimal Please help

kolezko [41]

Answer:

160/100=1.6

Step-by-step explanation:

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3 years ago

Answer the two questions below

STALIN [3.7K]

Answer:

3: No

4: 25

Step-by-step explanation:

3: It won't because not everyone is the same height and there will be variation in the mean height.

4: A larger sample size will give a more accurate representation of the population, where as a sample size of 5 is much more likely to have a higher percentage of outliers, and each outlier matters much more in finding the mean. In a sample size of 25, each outlier matters much less.

8 0

2 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

<u>Trigonometric Identities</u>

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

7 0

2 years ago

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