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3 years ago

Which number is greater than (>) 6.841?

1 answer:

6 0

6.842 or higher. When you line up the decimals, you see 6.842 has a 2 and 6.841 has a 1. 2 is greater than 1, more greater numbers are 6.843, 6.844, 6.845, etc.

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{ x + y = -2 { x - y = -8

g100num [7]

Answer:

(-5, 3)

Step-by-step explanation:

Elimination seems like the best method to use here.

x+y=-2

x-y=-8

---------

2x=-10

Divide everything by two

x=-5

Now plug it back into one of the original equations,

-5+y=-2

Add 5 to everything

y=3

7 0

3 years ago

Read 2 more answers

A train travels at a constant speed of 35 feet per second. How many minutes will it take the train to travel exactly 70 miles? (

olga_2 [115]

176 minutes,

70x5,280= 369,600 divide by 35= 10,560 divide by 60=176

3 0

4 years ago

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What is the lcm of 6 and 8

jeka57 [31]

Answer:

The LCM, or least common multiple, of 6 and 8 is 24.

3 0

3 years ago

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Determine a series of transformations that would map Figure G onto Figure H. I need help ASAPPP PLEASEEE

pshichka [43]

Answer:

A translation followed by a rotation would do it if they are congruent, which they should be.

Step-by-step explanation:

A transformation to move the corresponding points of each shape to the other, and a rotation to rotate the shape until the shapes map onto each other.

5 0

3 years ago

Beatriz went on a road trip. By the end of the first day, she was 200\text{ km}200 km200, end text from the starting point of he

vlada-n [284]

The direction of Beatriz relative to the starting point of her trip is approximately $278.806^{\circ}$ .

<h3>How to find the position of Beatriz relative to the starting point of her trip</h3>

After a careful reading of the statement, we find that final position ( $\vec r$ ) by the end of the second day is found by means of this vector sum:

$\vec r = \vec r_{1} + \vec r_{2}$ (1)

Where:

$\vec r_{1}$ - Vector distance of the first day relative to starting point, in kilometers.
$\vec r_{2}$ - Vector distance of the second day relative to the final point of $\vec r_{1}$ , in kilometers.

If we know that $\vec r_{1} = (200\,km \cdot \cos 300^{\circ}, 200\,km\cdot \sin 300^{\circ})$ and $\vec r_{2} = (150\,km\cdot \cos 250^{\circ}, 150\,km\cdot \sin 250^{\circ})$ , then final position of Beatriz relative to origin is:

$\vec r = (200\,km\cdot \cos 300^{\circ}, 200\,km\cdot \sin 300^{\circ})+(150\,km \cdot \cos 250^{\circ}, 150\,km\cdot \sin 250^{\circ})$

$\vec r = (48.670, -314.159)\,[km]$

And the direction relative to the starting point ( $\theta$ ), in degrees, is found by following inverse trigonometric relation:

$\theta = \tan^{-1} \frac{r_{y}}{r_{x}}$ (2)

If we know that $r_{x} = 48.670\,km$ and $r_{y} = -314.159\,km$ , then the direction of Beatriz relative to the starting point of her trip is:

$\theta = \tan^{-1} \left(\frac{-314.159\,km}{48.670\,km} \right)$

$\theta \approx 278.806^{\circ}$

The direction of Beatriz relative to the starting point of her trip is approximately $278.806^{\circ}$ . $\blacksquare$

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479

6 0

3 years ago