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Mashutka [201]
3 years ago
11

What volume does 2.25g of nitrogen gas, N2, occupy at 273 Celsius and 1.02 atm​

Chemistry
1 answer:
kotykmax [81]3 years ago
5 0
<h2><u>Answer:</u></h2>

0.126 Liters

<h2><u>Explanation:</u></h2>

V = mRT / mmP

First, convert the 2.25g of Nitrogen gas into moles. (m in the equation above)

2.25g x 1 mole / 28.0g = 0.08036 moles = m

28.0g = mm

Next, convert the 273 Celsius into Kelvin. (T in the equation above)

273 Celsius + 273.15 = 546.15K = T

R = 0.08206L*atm/mol*K

(Quick Note: The R changes depending on the Pressure Unit so do not use this number every time.)

Now, plug everything into the equation.

V = (0.08036)(0.08206)(546.15)/(28.0)(1.02)

V = 0.126 L

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For each of the following cases, identify the order with respect to the reactant, A. Case (A ----&gt; product)
damaskus [11]

Answer:

The answers to the question are

1. 2nd and above order order

2. 2nd order

3. 1/2 order

4.  1st order

5. 0 order

Explanation:

We have \frac{N}{N_{0} } = e^{-\lambda t}

1. For nth order reaction half life  t_{\frac{1}{2} } ∝ \frac{1}{[A_{0} ]^{n-1} }

Therefore for a 0 order reaction increasing concentration of the reactant there will increase   t_{\frac{1}{2} }

First order reaction    is independent  [A₀].

Second order reaction  [A₀] decrease,    increase.

Similarly for a  third order reaction

1. 2nd order

2. 2nd order reaction

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4. 1st order reaction.

5. Zero order reaction.

5 0
3 years ago
True or false: The Earth's rotation causes the winds to curve.
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Answer:

true

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3 0
3 years ago
A gaseous mixture consisting of nitrogen, argon, and oxygen is in a 3.5-L vessel at 25C. Determine the number of moles of oxygen
Step2247 [10]

Answer:

Number of moles of oxygen = 0.037  mol

Explanation:

Given data:

Total pressure = 98.5 KPa

Partial pressure of nitrogen = 22.0 KPa

Partial pressure of argon = 50.0 KPa

Volume = 3.5 L

Temperature = 25°C (25+273= 298K)

Number of moles of oxygen = ?

Solution:

Total pressure = P(N₂) + P(O₂) + P(Ar)

98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa

98.5 KPa = 72.0 KPa +P(O₂)

P(O₂)  = 98.5 KPa - 72.0 KPa

P(O₂)  = 26.5 KPa

KPa to atm:

26.5 KPa/ 101 = 0.262 atm

Number of moles of oxygen:

PV = nRT

n = PV/RT

n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K  × 298 K

n = 0.917atm.L /24.47atm.L/ mol

n = 0.037  mol

6 0
3 years ago
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3 years ago
Read 2 more answers
How many molecular of H2O and O2 are present in 8.5g of H2O2 ?​
Mama L [17]

2H2O+O2--->2H2O2  

8.5 gm H2O2=0.25 mole  

hence H2O is also 0.25 mole i.e.4.5 gm  

O2is 0.125 mole i.e.4 gm

4 0
3 years ago
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