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oee [108]
2 years ago
11

The melting points of alkaline earth metals are many times higher than those of the alkali metals. Explain this difference on th

e basis of atomic properties. Name three other physical properties for which Group 2A(2) metals have higher values than the corresponding 1A(1) metals.
Chemistry
1 answer:
7nadin3 [17]2 years ago
3 0

The correct answer is higher melting point, bound by metal metal bonds.

While alkali metals only have one valence electron, alkaline earth metals have two. Metal to metal connections hold the metals together. Alkaline earth metals have a stronger metallic connection and a higher melting point because they have two valence electrons.

the characteristics that Group 2 metals excel in over Group 1 metals.

  • Initial Ionization Potential
  • Group 2 items are more difficult than group 1 elements.
  • Strong propensity to produce bivalent compounds

As a result, group 2 metals have stronger metallic bonding, which leads to increased cohesive energy and compact atom packing. This explains why group 2 metals are harder and have higher melting and boiling temperatures than group 1 metals.

To learn more about  Group 2A(2) refer the link:

brainly.com/question/9431096

#SPJ4

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Predict the shape of the molecule.
GuDViN [60]

Number of electron pairs = \frac{1}{2}[V+N-C+A]

2

1

[V+N−C+A]

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

SbCl_5SbCl

5

:

In the given molecule, antimony is the central atom and there are five chlorine as monovalent atoms.

The number of electron pairs are 5 that means the hybridization will be sp^3dsp

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B and geometry of the molecule will be trigonal bipyramidal.

6 0
2 years ago
Chlorine has two isotopes, 35Cl and 37Cl; 75.77 % of chlorine is 35Cl and 24.23 % is 37Cl. The atomic mass of 35Cl is 34.969 amu
storchak [24]

Answer:

35.4528731 amu

Explanation:

To appropriately get the atomic mass unit of chlorine, we can get the answer using the masses from the isotopes. This can be obtained as follows. What we do is that we multiply the percentage compositions by the masses.

Now let’s do this.

[75.77/100 * 34.969] + [24.23/100 * 36.966]

= 26.4960113 + 8.9568618 = 35.4528731

3 0
3 years ago
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anzhelika [568]

Answer:

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3 0
2 years ago
BRAINLIEST WILL BE GIVEN!! FAST PLEASE!
WARRIOR [948]

Answer:

1) THE AGE OF THE SAMPLE 2) URANIUM- LEAD DATING

Explanation:

3 0
3 years ago
If you have 3.01 E24 molecules of CO, how many moles of CO do you have?
MA_775_DIABLO [31]

Answer: 5moles

Explanation:

1mole of a substance contains 6.02x10^23 molecules.

Then, 1mole of CO also contains 6.02x10^23 molecules.

If 1 mole of CO2 contains 6.02x10^23 molecules, it means Xmol of CO contains 3.01 E24 ie 3.01x10^24 molecules

Xmol of CO = 3.01x10^24 / 6.02x10^23

Xmol = 5moles

5 0
3 years ago
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