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3 years ago

James has some apples and oranges. The ratio of apples and oranges is 2:5 He has 15 oranges.

Mathematics

1 answer:

patriot [66]3 years ago

5 0

Answer:

6 apples

Step-by-step explanation:

so basically if the ratio is 2:5

then divide 15/5

so you know that each proportion is 3

then 3x2=6

so the ans is 6

pls mark me brainliest

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Y=2x+1 answers anyone?

laila [671]

Answer: y= 2

Step by step: Multiply 2 and 1 to get 2

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3 years ago

Find the area of an equilateral triangle with side length 9.2 cm. Round your answer to 1 DP.

lbvjy [14]

Answer:

Area=36.66 cm^2

Step-by-step explanation:

First, you need the height.

Use the Pythagorean theorem:

hypotenuse^2=height^2+(1/2 base)^2

It's one-half base because it's an equilateral triangle.

1/2 base =4.6

(9.2)^2-4.6^2=height^2

84.64-21.16=height^2

height^2=63.48

height=7.97

Area=(1/2)(base)(height)

Area=(1/2)(9.2)(7.97)=36.66 cm^2

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2 years ago

A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9, and the sample stand

yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

Step 1: We state the hypothesis and identify the claim

$H_0:\mu=100$ and $H_1:\mu \:>\:100$ (claim)

Step 2: Calculate the test value.

$t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$

$\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263$

Step 3: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

Step 4: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).

Step 5: There is enough evidence to support the claim that the population mean is greater than 100.

Alternatively: We could also calculate the critical value to obtain +1.685 for $\alpha=0.05$ and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0

3 years ago

Records show that 12% of all college students are foreign students who also smoke. It is also known that 40% of all foreign coll

Sati [7]

Answer: the percent of the students at this university are foreign = 30%

Step-by-step explanation:

Given: Probability that college students are foreign students who also smoke: P(S|F)=0.12

Probability that foreign college students smoke P(S∩F)=0.4

The probability that the students at this university are foreign :

$P(F)=\dfrac{P(S\cap F)}{P(S|F)}$ [By conditional probability formula]

$=\dfrac{0.12}{0.4}\\\\=0.3$

Hence, the percent of the students at this university are foreign = 30%

6 0

2 years ago

What the expanded form of 8.65?

Stells [14]

Answer:

8 .60 .05

Hope it helps :D

btw pls mark brainlest

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3 years ago