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barxatty [35]
2 years ago
14

Match each substance with the correct designation for the equation HSO3- + CH3NH2 <=> SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C

H3NH3+ A. conjugate base of HSO3- B. conjugate acid of SO32- C. conjugate acid of CH3NH2 D. conjugate base of CH3NH3+
Chemistry
1 answer:
Zanzabum2 years ago
4 0

Answer:

HSO_3^-: conjugate acid of SO_3^{2-}

CH_3NH_2 : conjugate base of CH_3NH_3^+

SO_3^{2-} : conjugate base of HSO_3^-

CH_3NH_3^+ : conjugate acid of CH_3NH_2

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+

Here in forward reaction CH_3NH_2 is accepting a proton, thus it is considered as a base and after accepting a proton, it forms CH_3NH_3^+ which is a conjugate acid.

And HSO_3^-  is losing a proton, thus it is considered as an acid and after loosing a proton, it forms SO_3^{2-} which is a conjugate base.

Similarly in the backward reaction, CH_3NH_3^+ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms CH_3NH_2 which is a conjugate base.

And SO_3^{2-}  is accepting a proton, thus it is considered as a base and after accepting a proton, it forms HSO_3^{-} which is a conjugate acid.

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Explanation:

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5 0
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27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional a
jok3333 [9.3K]

Answer : The volume of the cube is, 21.88cm^3

Solution : Given,

Density of nickel = 8.91g/cm^3

Number of nickel atoms = 2\times 10^{24}

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, 6.022\times 10^{23} atoms form 1 mole of nickel

So, 2\times 10^{24} atoms form \frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321 moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}

\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

Density=\frac{Mass}{Volume}

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In a study of the conversion of methane to other fuels, a chemical engineer mixes gaseous methane and gaseous water in a 0.778 L
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Answer:

the water concentration at equilibrium is

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Explanation:

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∴ Kc = ( [ CO(g) ] * [ H2 ]³ ) / ( [ CH4(g) ] * [ H2O(g) ] ) = 0,30

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⇒ [ H2(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L

⇒ [ CH4(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L

replacing in Kc:

⇒ ((0.2648) * (0.2404)³) / ([ H2O(g) ] * 0.2404 ) = 0.30

⇒ 0.0721 [ H2O(g) ] = 3.679 E-3

⇒ [ H2O(g) ] = 0.0510 mol/L

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