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DaniilM [7]
3 years ago
5

A 2.0 L solution made by adding solid NaClO to water resulted in a basic equilibrium with a pH of 10.50. How many moles of NaClO

were originally added? Ka of HClO is 3.0 × 10⁻⁷.
Chemistry
1 answer:
Pavel [41]3 years ago
5 0

Answer:

0.66 moles of NaClO were originally added

Explanation:

When NaClO is added to water, the equilibrium that occurs is:

NaClO(aq) + H₂O(l) ⇄ HClO(aq) + OH⁻(aq)

Where Kb is:

Kb = [HClO] [OH⁻] / [NaClO]

You can obtain Kb from Ka, thus:

Kb = Kw / Ka = 1x10⁻¹⁴ / 3.0x10⁻⁷

Kb = 3.33x10⁻⁸

As pH = 10.50;

pOH = 14 - 10.50 = 3.50

[OH⁻] = 10^{-3.50}

[OH⁻] = 3.16x10⁻⁴M

As OH⁻ and HClO comes from the same equilibrium, [OH⁻] = [HClO]

Replacing in Kb expression:

Kb = [HClO] [OH⁻] / [NaClO]

3.33x10⁻⁸ = [3.16x10⁻⁴] [3.16x10⁻⁴] / [NaClO]

[NaClO] = 0.333M

As there are 2.0L of NaClO solution, moles added were:

2.0L * (0.33moles / L) =

<h3>0.66 moles of NaClO were originally added</h3>

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5.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 13
Nimfa-mama [501]

Answer:

The molecular formula is C8H8O2

Explanation:

Step 1: Data given

Mass of compound X = 5.50 grams

Mass of CO2 = 14.24 grams

Molar mass of CO2 = 44.01 g/mol

Mass of H2O = 2.91 grams

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

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Molar mass H = 1.01 g/mol

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Moles CO2 = 14.24 grams / 44.01 g/mol

Moles CO2 = 0.324 moles

Step 3: Calculate moles C

For 1 mol cO2 we have 1 mol C

For 0.324 moles CO2 we have 0.324 moles C

Step 4: Calculate mass C

Mass C = 0.324 moles * 12.01 g/mol

Mass C = 3.89 grams

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Moles H2O = 0.161 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.161 moles H2O we have 2*0.161 = 0.322 moles H

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Mass H = 0.322 moles * 1.01 g/mol

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Step 9: Calculate moles O

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Moles O = 0.0803 moles

Step 10: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.324 moles / 0.0803 moles = 4

H: 0.322 moles / 0.0803 moles = 4

O: 0.0803 moles / 0.0803 moles = 1

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The molar mass of this empirical formula is 68 g/mol

Step 11: Calculate the molecular formula

We have to multiply the empirical formula by n

n = 136 g/mol / 68 g/mol

n = 2

We have to multiply the empirical formula by 2

Molecular formula = 2*(C4H4O) = C8H8O2

The molecular formula is C8H8O2

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