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2 years ago

Determine the volume of the graduated cylinder below

Chemistry

1 answer:

andreyandreev [35.5K]2 years ago

3 0

Answer:

its around 12.7

Explanation:

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A 2.2 M solution is made by with 0.45 moles of a solute. What is the final volume of this solution?

Savatey [412]

Answer: The final volume of this solution is 0.204 L.

Explanation:

Given: Molarity of solution = 2.2 M

Moles of solute = 0.45 mol

Molarity is the number of moles of solute present divided by volume in liters.

$Molarity = \frac{no. of moles}{Volume (in L)}$

Substitute the values into above formula as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\2.2 M = \frac{0.45}{Volume}\\Volume = 0.204 L$

Thus, we can conclude that the final volume of this solution is 0.204 L.

7 0

3 years ago

1. The two qualities used to describe winds are________ and speed. 2. a local wing that blows during the day from an ocean towar

Mazyrski [523]

<span>1. The two qualities used to describe winds are direction and speed.
2. a local wind that blows during the day from an ocean toward land is a(n) sea breeze.
3. The increase in cooling that wind can cause is called the wind-chill factor.
4. Temperature differences between the equator and poles produce convection currents.
A movement that is parallel to Earth's Surface is called wind and a local wind is that wind that blows over a short distance.</span>

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3 years ago

A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0

3 years ago

Why is it impossible to have an undiscovered element that would fit between sodium and magnesuim

Stolb23 [73]

Answer:

Sodium has 11 protons and Magnesium has 12. The way that the periodic table is set up doesn't allow for any elements to be in between. The element would have to have 11.5 protons, which is impossible

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2 years ago

Which highway run through comlumbus

Alexeev081 [22]

Answer:

Highway 22 ,GA 31820

Explanation:

3 0

3 years ago