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Rzqust [24]
3 years ago
14

An unknown compound has the following chemical formula:

Chemistry
1 answer:
noname [10]3 years ago
7 0

Answer:

The chemical formula of the compound is P_2O_5.

Explanation:

In 1 mole of P_2O_x there are 2 moles of phosphorus atom.

Then 3.3 moles of phosphorus will be in :

\frac{1}{2}\times 3.3 mol=1.65 moles

In 1 mole of P_2O_x there are x moles of oxygen atom.Then 1.65 moles of compound will have :

1.65 mol\times x

Moles of oxygen in 1.65 moles of compound = 8.20 mol

1.65 mol\times x=8.20 mol

x=\frac{8.20 mol}{1.65 mol}=4.9 \approx 5

The chemical formula of the compound is P_2O_5.

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Answer:

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6 0
3 years ago
If you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
irakobra [83]

Answer:

0.22

Explanation:

Given, Mass of C_{18}H_{21}NO_3 = 46.85 g

Molar mass of C_{18}H_{21}NO_3 = 299.4 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{46.85\ g}{299.4\ g/mol}

Moles\ of\ C_{18}H_{21}NO_3= 0.1565\ mol

Given, Mass of C_{2}H_{5}OH = 125.5 g

Molar mass of C_{2}H_{5}OH = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{125.5\ g}{46.07\ g/mol}

Moles\ of\ C_{2}H_{5}OH= 0.5535\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ codeine=\frac {n_{codeine}}{n_{codeine}+n_{ethanol}}

Mole\ fraction\ of\ codeine=\frac{0.1565}{0.1565+0.5535}=0.22

4 0
3 years ago
If the rate law for a reaction A → P is rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122 M, calcula
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Rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122M.

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3 0
2 years ago
How many valence electrons does Nitrogen have?​
irinina [24]

Answer:

5 valence electrons

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Explanation:

6 0
3 years ago
NaOH  + H2SO4 =
mariarad [96]
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