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Elza [17]
3 years ago
8

N DevOps, high levels of automation are expected, which increases productivity. Which fact illustrates this productivity increas

e?
Engineering
1 answer:
Bess [88]3 years ago
3 0

Answer:

Less intervention of humans.

Explanation:

This fact illustrate that less intervention of human in the production is the main cause for increase in productivity because use of machinery completed the work in less time as compared to the use of human labour. In many industries, machines takes the place of humans which increases the production of products but at the same time, increase the unemployment rate in the society. Making the whole industry on automation can increase the productivity of products in less time.

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Write a program. Submit a file named height.c Amusement parks have minimum heights for their rides. Create a program that adds u
Natasha_Volkova [10]

Answer:

you ok

Explanation:

try it

8 0
3 years ago
A resistor R = 1 kohm an inductor L = 1 mH and a capacitor C = 1 muFare used in a circuit which is driven by a voltage source v_
shusha [124]

Answer:

A = 10, B = -45

Explanation:

Given a voltage source of the form A\cos(\omega t + \phi) the correspondent phasor is of the form A\angle \phi. Note that the phasor form is only considered for sources expressed in a cosine form. IN this case, since the question is only asking for the phasor of the voltage form, the way the other devices are connected is neglected and do not affect the answer. Then, to get the phasor of the voltage source, we need to express it in a cosine form. To do so, the following trigonometric equation is used \sin(\omega t + \phi) = \cos (\omega t +\phi - 90^\circ)

Therefore, the voltage source, in terms of cosine, is equivalent to 10 \cos(10^5 t +45^\circ- 90^\circ)= 10 \cos(10^5 t -45 ^\circ ), so the correspondent phasor form is 10\angle -45.

5 0
4 years ago
A gas is compressed isothermally in a piston-cylinder assembly from 7.6 bar, 77 °C to 3.05 bar. Determine the work and heat tran
yaroslaw [1]

Answer:

The work done or the heat transfer for air and hydrogen are 91.71 kj/kg and 1317.89 kj/kg respectively.

Explanation:

Given:

Initial pressure is 7.6 bar.

Initial temperature is 77 °C.

Final pressure is 3.05 bar.

Calculation:

(a)

Take air as an ideal gas with gas constant 0.287 kj/kgK.  

Step1

For isothermal process work done and heat transfer is the same because of no change in internal energy.

Work done is calculated as follows:

W=RT_{1}ln\frac{P_{1}}{P_{2}}

W=0.287(77+273)ln\frac{7.6}{3.05}

W = 91.71 kj/kg.

Thus, the work done or the heat transfer for isothermal process is 91.71 kj/kg.

Step2

For isothermal process work done and heat transfer is the same because of no change in internal energy. Take Hydrogen as an ideal gas with gas constant 4.1242 kj/kgK.

Work done is calculated as follows:

W=RT_{1}ln\frac{P_{1}}{P_{2}}

W=4.1242(77+273)ln\frac{7.6}{3.05}

W = 1317.89 kj/kg.

Thus, the work done or the heat transfer for isothermal process is 1317.89 kj/kg.

4 0
3 years ago
Process synchronization can be done on
marishachu [46]

Answer:

it is c) both (a) and (b)

Explanation:

5 0
3 years ago
Determine the following for a south facing surface at 30� slope in
lesantik [10]

Answer:

z=60.32°, i=0.32°, Beam Radiation = 1097.2 W/m²,  Id = 94.2 W/m², Ir=14.1W/m², total radiation = 1205.4 W/m², Local time=1:21PM

Explanation:

A. Zenith Angle:

As we know that,

Zenith angle=z=90⁰-α=L(latitude)=29.68⁰

Another way to do it is to find α first,

At solar time hour angle is 0⁰. So, solar altitude becomes equal to latitude which could be written as

sinα=cosL

α=sin⁻¹(cosL)=sin⁻¹(cos29.68⁰)=60.32°

B. Angle of incidence:

angle of incidence= cosi=sin(α+β)=sin(60.32°+32°)=sin92.32°

i=cos⁻¹(sin92.32°)=0.32°

C. Beam Radiation:

First we need to calculate extra terrestrial radiations

Iext.=1353[1+0.034cos(360n/365)]

where n=264

=1345 W/m²

Now,

Beam Radiation=CIext⁻ⁿ

where n=0.1/sin60.32°

Beam Radiation = 1097.2 W/m²

D. Diffude Radiation:

difuse radiation = Id = 0.0921ₙcos²(β/2)

where β=30°

Id = 94.2 W/m²

E. Reflected Radiations:

Ir=pIn(sinα+0.092)sin²(β/2)

= (0.2)(1097.1)(sin60.32+0.092)sin²(30/2)

= 14.1W/m²

F. Total Radiation:

total radiation = beam radiation + diffuse radiation + reflected raddiation

= 1205.4 W/m²

G. Local Time:

LST= ST-ET-(lₓ-l(local))4min/₀

     = 12:00-7.9min-(75°-82.27°)4min/₀

     =12:21PM

Local time

LDT=LST+=12:21+1:00=1:21PM

5 0
3 years ago
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