Answer: The value of the equilibrium constant, Kc, for the reaction is 0.013
Explanation:
Initial concentration of
= 3.60 M
Initial concentration of
= 3.60 M
The given balanced equilibrium reaction is,

Initial conc. 3.60 M 3.60 M 0 M 0 M
At eqm. conc. (3.60-4x) M (3.60-7x) M (2x) M (6x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[N_2O_4]^2\times [H_2O]^6}{[NH_3]^4\times[Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BN_2O_4%5D%5E2%5Ctimes%20%5BH_2O%5D%5E6%7D%7B%5BNH_3%5D%5E4%5Ctimes%5BCl_2%5D%7D)
![[N_2O_4]=0.60M](https://tex.z-dn.net/?f=%5BN_2O_4%5D%3D0.60M)
2x = 0.60 M
x= 0.30 M
Now put all the given values in this expression, we get :


Answer: Its "C"
Explanation:
Appearance and density
sorry this took 14 hours lol
pls mark brainiest
Answer:
7.6 days
Explanation:
Radon is a radioactive element and Radon-222 is it's most stable isotope. The half-life of Radon-222 has been found to be approximately 3.8 days.
Let, the initial amount of the Rn-222 = 1 = A
Final amount =
= A'
We will use the following relation for calculating time elapsed in the decay

Thus,

We can write is as,

Since the base in both sides are equal, powers can also be equal and thus,

So, t = 7.6 days
D) The same number of each type of atom will always be present before and after a chemical reaction takes place.
Mass is never created or lost in a chemical reaction, so the atoms of each element must stay balanced.
Answer:
I know 2
dependent
independent
Explanation:
sorry that's about it from me