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Marianna [84]
3 years ago
5

Question 8 1.2 pts an atom of bromine has a mass about four times greater than that of an atom of neon. which choice makes the c

orrect comparison of the relative numbers of bromine and neon atoms in 1,000 g of each element?
Chemistry
1 answer:
Scorpion4ik [409]3 years ago
8 0
Neon = app. 20.1795 g/mol 
<span>Bromine = app. 79.904 g/mol </span>
<span>-----> 79.904 g/mol / 20.1795 g/mol = 3.96 (Close to 4) </span>

<span>Using Moles In 1000 g </span>

<span>1000 g / 20.1795 g/mol = app. 49.555 mol of Ne </span>
<span>1000 g / 79.904 g/mol = app. 12.515 mol of Br </span>
<span>-----> 49.555 mol / 12.515 mol = 3.96 (Close to 4) </span>

<span>Using Avogadro's Number </span>

<span>49.555 mol x 6.022x10^23 atoms = app. 2.984x10^25 atoms of Ne </span>
<span>12.515 mol x 6.022x10^23 atoms = app. 7.537x10^24 atoms of Br </span>
<span>-----> 2.984x10^25 / 7.537x10^24 = 3.96 (Close to 4) </span>

<span>So no matter how you look at it or calculate it, the answer is always the same. </span>

<span>I hope it helps!</span>
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Please help, with step by step work
natali 33 [55]

\qquad ☀️\pink{\bf{ {Answer  = \: \:   85.57g }}}

Molar mass of \bf Cu_2O

\qquad \twoheadrightarrow\sf 63.546 \times 2 +16

\qquad \pink{\twoheadrightarrow\bf 143.092 g}

<u>As we know</u>–

1 mol =\bf 6.02×10^{23} formula units

1 mol\bf Cu_2O = 143.092 g = \bf 6.02×10^{23}formula units

Henceforth –

\bf 3.60×10^{23} formula units \bf Cu_2O–

\qquad \sf :\implies \dfrac{143.092 \times3.60×10^{23  }}{6.02×10^{23}}

\qquad \sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23  }}}{6.02×\cancel{10^{23}}}

\qquad \pink{:\implies\bf 85.57 g}

5 0
2 years ago
A 6.165 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 10.27 grams of CO2 and 3
e-lub [12.9K]

Answer:

Explanation:

mass of carbon in 10.27 g of CO₂ = 12 x 10.27 / 44 = 2.80 g

mass of hydrogen ( H ) in 3.363 g of H₂O = 2  x 3.363 / 18

= .373 g

These masses would have come from the sample of 6.165 g .

Rest of 6.165 g of sample is oxygen .

So oxygen in the sample = 6.165 - ( 2.8 + .373 ) = 2.992 g

Ratio of C  , H , O in the sample

2.8 : .373 : 2.992

C: H : O : : 2.8 : .373 : 2.992

Ratio of moles

C: H : O : : 2.8/12 : .373/1 : 2.992 / 16

C: H : O : : .2333 : .373 : .187

C: H : O : : .2333/.187 : .373/.187 : .187/.187

C: H : O : : 1.247 : 1.99 : 1

C: H : O : : 5 : 8 : 4 ( after multiplying by 4 )

Hence empirical formula

C₅H₈O₄

Molecular formula ( C₅H₈O₄ )n

n ( 5 x 12 + 8 x 1 + 4 x 16 ) = 132

n x ( 60 + 8 + 64 ) = 132

n = 1

Molecular formula = C₅H₈O₄.

3 0
2 years ago
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Answer:

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Explanation:

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3 years ago
Atoms,which are always neutral in electric charge, contain electrons as well as protons and neutrons. An electron has an electri
creativ13 [48]

Answer:

3

Explanation:

Since the atom has three electrons, it has a -3 electrical charge. Since atoms are neutral, 3 protons are needed to get the charge back to 0.

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I just got this question and it was lipids sorry if i’m wrong
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