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2 years ago

4.1.2 Quiz: What is scientific notation?

Chemistry

1 answer:

Eddi Din [679]2 years ago

3 0

Answer:

D. Scientific notation is a way of writing large and small numbers

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Is A tomato smells rotten a chemical<br> reaction

olganol [36]

Answer:

yup

Explanation:

because chemical change took place

the reaction cant be reversible

6 0

3 years ago

Read 2 more answers

A student does an experiment to determine the molar solubility of lead(II) bromide. She constructs a voltaic cell at 298 K consi

attashe74 [19]

Answer:

The molar solubility of lead bromide at 298K is 0.010 mol/L.

Explanation:

In order to solve this problem, we need to use the Nernst Equaiton:

$E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}$

E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.

At equilibrium, E = 0, therefore:

$E^{o} = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] = log[ox] - \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] - \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 - \frac{2x5.45x10^{-2} }{0.0591}}\\\\$

[red] = 0.010 M

The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.

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3 years ago

What is back titration?

Yakvenalex [24]

Answer:

Back titration is a titration done in reverse; instead of titrating the original sample, a known excess of standard reagent is added to the solution, and the excess is titrated.

I hope it's helpful!

3 0

2 years ago

How many moles are in 4.6 x 10^19 atoms? <br><br> *#27 is the question

velikii [3]

There are 0.000076 moles in 4.6 x 10^19 atoms.

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3 years ago

Ann and Carol each lift the timber with a force of 80 kg/m/s2. If they lift the timber a distance of 1.25 meters, how much work

Novosadov [1.4K]

Work is defined energy transferred from one to another.
The formula for work done is work done = force x distance

So in our problem, force is equal to 80 kg/ m / s^2 and distance is equal to 1.25 meters. So plugging in our values will give us:

work done = 80 kg/ m/ s^2 * 1.25 m
= 100.00 J is the answer.

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2 years ago