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Tcecarenko [31]
3 years ago
11

Which two options are examples of waves diffracting?

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0

Answer:

B and D

Explanation:

Diffraction refers to the bending of waves either around an obstacle or through a gap.

A is not diffraction because although it involves the bending of light, it is due to travelling between mediums instead of bending around an obstacle or through a gap, (A is referring to refraction).

B is an example of diffraction because it is referring to the bending of the sound waves as it passes through a gap (a door) which is why it is amplified.

C is not an example of diffraction as the light waves do not bend, they simply bounce back from the mirror surface to form the image (reflection).

Finally, D is diffraction because the waves are passing though a gap in a barrier and will bend as a result due to diffraction.

Hope this helped!

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Explanation:

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In kw it's going to be 600/1000=0.6kw

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Answer:

Force = 186 N

Explanation:

Torque is the rotational equivalent of linear force. It can be easely calculated using the formula :

Torque = \vec{r} \times \vec{F}

Where \vec{r} is a vector that from the origin of the coordinate system to the point at which the force is applied (the position vector), \vec{F} is the applied force.

The easiest way of computing the force is by setting the origin of the coordinate system to the lowest point of the torque wrench.  By doing this we have that r (the magnitud of the position vector) is 35cm.

Before computing the force we need to set all our values to the international system of units (SI). The torque is already in SI. The one missing is the length of the torque wrench (it is in centimeters and we need it in meters). So :

35cm * \dfrac{1m}{100cm} = 0.35m

Now using the torque formula:

Torque = \vec{r} \times \vec{F}

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Where \theta is the smaller angle between the force and the position vector. Because the force is applied perpendiculary to the position vector  \theta = 90°, thus :

Torque = rFsin(\theta)}

65 N m = (0.35m)Fsin(90°)}

F = \dfrac{65N m} {(0.35m)sin(90°)}

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F = \dfrac{1300} {7}N

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Answer:

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