The magnitude of the magnetic field inside the solenoid is
.
The given parameters;
- <em>length of the solenoid, L = 91 cm = 0.91 m</em>
- <em>radius of the solenoid, r = 1.5 cm = 0.015 m</em>
- <em>number of turns of the solenoid, N = 1300 </em>
- <em>current in the solenoid, I = 3.6 A</em>
The magnitude of the magnetic field inside the solenoid is calculated as;

where;
is the permeability of frees space = 4π x 10⁻⁷ T.m/A

Thus, the magnitude of the magnetic field inside the solenoid is
.
Learn more here:brainly.com/question/17137684
<u>Answer:</u> The voltage needed is 35.7 V
<u>Explanation:</u>
Assuming that the resistors are arranged in parallel combination.
For the resistors arranged in parallel combination:

We are given:

Using above equation, we get:

Calculating the voltage by using Ohm's law:
.....(1)
where,
V = voltage applied
I = Current = 3.75 A
R = Resistance = 
Putting values in equation 1, we get:

Hence, the voltage needed is 35.7 V
Answer:
In the picture.
Explanation:
I hope that it's a clear solution.