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butalik [34]
4 years ago
14

Calculate the potential energy of a 20-kg sled at 40 meters

Physics
2 answers:
irakobra [83]4 years ago
5 0

Answer: 7840N

Explanation:

Given that

Potential energy = ?

Mass of sled = 20-kg

Distance = 40 meters

Acceleration due to gravity = 9.8m/s^2

Recall that potential energy is the energy possessed by a body at rest

i.e potential energy = mass m x acceleration due to gravity g x distance h

P.E = mgh

P.E = 20kg x 9.8m/s^2 x 40m

P.E = 7840N

Thus, the potential energy of the sled is 7840N

Natali [406]4 years ago
4 0
The above answer is correct however gravitational potential energy is measured in joules. So the final answer would be 7840 J (joules) not newton’s.
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a 5.0 kg block is at rest on a horizontal floor. if you push horizontally on the 5.0 kg block with a force of 15.0 n, it just st
zheka24 [161]

For the 5.0Kg block with the force of 15 Newton, the coefficient of static friction (μ) comes out to be 0.306. Applying the formula F = μmg.

Static friction acts on stationary body/body at rest. Let μ be the coefficient of static friction between the block and the horizontal floor.

Using the formula: F = μmg

Where,

F = Force , m= mass of the block and g = gravity.

and values of: m= 5.0Kg, F= 15.0N, g= 9.8m/s²

We can get: μ = F/(mg)

μ = 15/49

μ =0.306

Therefore, coefficient of static friction (μ) = 0.306.

To learn more about static friction visit the link- brainly.com/question/13680415

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4 0
2 years ago
Calculate the upthrust aciting on a body if its
Zepler [3.9K]

Answer:

As a body moving upward

T=real weight + apparent weight

T=550+490

T=1040

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Explanation:

7 0
3 years ago
Where is information first stored in a human brain​
Dmitrij [34]

Answer:

The long-term memories are stored throughout the brain as groups of neurons, the brain stores memories in three ways--Short-term memories, Sensory memory and Long-term memory the human brain cell can hold 5 times as much of information as the Encyclopedia Britannica.

Explanation:

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Which two properties of light relate to the amount of energy carried by the light? A. speed and amplitude
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C. color and wavelength
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3 years ago
Block 2 of mass 1.00 kg is at rest on a frictionless surface and touching the end of an unstretched spring of spring constant 20
son4ous [18]

Answer:

x = 0.327 m

Explanation:

Block 2 of mass 1.00 kg is at rest

spring constant = 200 N/m            

Block 1 of mass 2 kg moving at 4 m/s

m₁ v₁ = (m₁ + m₂)V                                

2 x 4 = (2 + 1) V                                                      

V = 2.67 m/s                                                        

loss of kinetic energy = gain elastic potential energy

\dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2                  

\dfrac{1}{2}\times (3)\times 2.67^2 = \dfrac{1}{2}\times 200 \times x^2

x = 0.327 m

hence, the spring compressed distance is equal to x = 0.327 m

8 0
3 years ago
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