Answer:
v₁ = 3.5 m/s
v₂ = 6.4 m/s
Explanation:
We have the following data:
m₁ = mass of trailing car = 400 kg
m₂ = mass of leading car = 400 kg
u₁ = initial speed of trailing car = 6.4 m/s
u₂ = initial speed of leading car = 3.5 m/s
v₁ = final speed of trailing car = ?
v₂ = final speed of leading car = ?
The final speed of the leading car is given by the following formula:
<u>v₂ = 6.4 m/s</u>
The final speed of the leading car is given by the following formula:
<u>v₁ = 3.5 m/s</u>
<span>Assuming that the momenta of the two pieces are equal: when they have equal velocities, then
the masses of the two pieces are also equal.
Since there is no force from outside of the system, the center of mass moves on with the same velocity as before the equation. So the two pieces must fly at the side side of the mass center, i.e., they must always be at 90° to the side of the mass center. Otherwise it would not be the mass center, respectively the pieces would not have equal velocities.
This is only possible, when the angle of their velocity with the initial direction is 60°.
Because, cos (60°) = 1/2 = v/(2v).</span>
-- The object either left or crossed the starting line exactly at time=0 .
-- The object has been traveling at constant speed for all time that
we know about.
Answer:
upwards
downwards
Explanation:
Given:
weight of the person, 
So, the mass of the person:
- Now if the apparent weight in the elevator,
<u>Then the difference between the two weights is :</u>
is the force that acts on the body which generates the acceleration.
Now the corresponding acceleration:
upwards, because the normal reaction that due to the weight of the body is increased here.
- Now if the apparent weight in the elevator,
<u>Then the difference between the two weights is :</u>
is the force that acts on the body which generates the acceleration.
Now the corresponding acceleration:
downwards, because the normal reaction that due to the weight of the body is decreased here.
