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andreyandreev [35.5K]

3 years ago

7

Harry collected green balls in a bag he drew two balls , of the five balls ,out of the bag. is this a random sample of windows i

n the bag

1 answer:

mafiozo [28]3 years ago

8 0

What,windows? well i i guess yes

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Need Assitance<br>*Show Work*

Rama09 [41]

Answer:

66 2/3 %

Step-by-step explanation:

First find the students not in the 8th grade

24 - 8 = 16

16 students are not in the 8th grade

Take the fraction of the students not in the 8th grade over the total

16/24 = 2/3

Change to a decimal

.66666666666

Multiply by 100 to change to a percent

66.666666%

66 2/3 %

6 0

3 years ago

Read 2 more answers

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

Find the geometric mean of 2 and 50

svet-max [94.6K]

Answer:

<h2><u>10</u></h2>

Step-by-step explanation:

x = √(2)(50)

⇒ x = √(100)

⇒ x = <u>10</u>

5 0

3 years ago

Read 2 more answers

What are the intercepts of 3x -4y=-24

masha68 [24]

Answer:

desmos

Step-by-step explanation:

look up desmos. its a grphing calculator and it gives u all the awnsers. welcome bro

6 0

2 years ago

Read 2 more answers

PLEASE HELPP I AM FAILING AND I NEED THIS ASAP!!! TYSM

Lana71 [14]

Answer:

See below for answers

Step-by-step explanation:

Do you mean $f(x)=2sin(x-1)$ or $f(x)=2sin(x) -1$ ?

Use the formula $f(x)=asin(bx+c)+d$ where $|a|$ is the amplitude, $-\frac{c}{b}$ is the phase shift, $d$ is the vertical shift, and the period is $\frac{2\pi}{|b|}$ .

Assuming your first case is true, the amplitude would be $|a|=|2|=2$ , your period is $\frac{2\pi}{|1|}=2\pi$ , and your midline/vertical shift is $d=0$ .

Assuming your second case is true, everything but the vertical shift stays the same. It would be $d=-1$ in this case.

5 0

2 years ago